Question in the attachments An object of height 79.2 cm is distance so = 80.4 cm from a concave mirror of focal length 9.62 cm. At t = 0 the shape of the mirror begins to change, so that the focal length isdecreasing at a constant rate:df= -1.93 cm/s.dtFind the rate at which the height of the image is changing, in cm/s. The sign will indicate if the value of the height of the image is increasing or decreasing.HINT: Again, beware of signs!

Given, object distance = -80.4 cm focal length = -9.62 cm

An object of height 79.2 cm is distance so = 80.4 cm from a concave mirror of focal length 9.62 cm. At t = 0 the shape of the mirror begins to change, so that the focal length is decreasing at a constant rate: = -1,93 cm/s. dt Find the rate at which the height of the image is changing, in cm/s. The sign will indicate if the value of the height of the image is increasing or decreasing. HINT: Again, beware of signs!

An object of height 79.2 cm is distance so = 80.4 cm from a concave mirror of focal length 9.62 cm. At t = 0 the shape of the mirror begins to change, so that the focal length is decreasing at a constant rate: = -1,93 cm/s. dt Find the rate at which the height of the image is changing, in cm/s. The sign will indicate if the value of the height of the image is increasing or decreasing. HINT: Again, beware of signs!