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An object of height 79.2 cm is distance so = 80.4 cm from a concave mirror of focal length 9.62 cm. At t = 0 the shape of the mirror begins to change, so that the focal length is decreasing at a constant rate: = -1,93 cm/s. dt Find the rate at which the height of the image is changing, in cm/s. The sign will indicate if the value of the height of the image is increasing or decreasing. HINT: Again, beware of signs!

An object of height 79.2 cm is distance so = 80.4 cm from a concave mirror of focal length 9.62 cm. At t = 0 the shape of the mirror begins to change, so that the focal length is decreasing at a constant rate: = -1,93 cm/s. dt Find the rate at which the height of the image is changing, in cm/s. The sign will indicate if the value of the height of the image is increasing or decreasing. HINT: Again, beware of signs!

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An object of height 79.2 cm is distance so = 80.4 cm from a concave mirror of focal length 9.62 cm. At t = 0 the shape of the mirror begins to change, so that the focal length is decreasing at a constant rate: df = -1.93 cm/s. dt Find the rate at which the height of the image is changing, in cm/s. The sign will indicate if the value of the height of the image is increasing or decreasing. HINT: Again, beware of signs!
Transcribed Image Text:An object of height 79.2 cm is distance so = 80.4 cm from a concave mirror of focal length 9.62 cm. At t = 0 the shape of the mirror begins to change, so that the focal length is decreasing at a constant rate: df = -1.93 cm/s. dt Find the rate at which the height of the image is changing, in cm/s. The sign will indicate if the value of the height of the image is increasing or decreasing. HINT: Again, beware of signs!
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