An object moves in simple harmonic motion with period 6 seconds and amplitude 3 cm. At time t=0 seconds, its displacement d from rest is 0 cm, and initially it moves in a negative direction.
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Q: The equation of motion of a particle in simple harmonic motion is given by: x(t) = 0.2cos(wt), where…
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Q: A particle undergoes simple harmonic motion with an amplitude of 3.00 cm. At what position (in cm)…
A: Here, Given Amplitude(A)=3 cm V=0.12Vmax
Q: The equation of motion of a particle in simple harmonic motion is given by: x(t) = 0.2cos(wt), where…
A: Given that:- X(t)=0.2cos(wt)
Q: What positive value of x/A gives v= 0.56 v_max, where A is the amplitude of the motion?
A: we have v=ωA2-x2vmax=Aω⇒v=vmaxAA2-x2=vmax1-x2A2
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Q: The velocities of a particle performing linear S.H.M. are 0.13 m/s and 0.12 m/s when it is at 0.12 m…
A: To find-(1) Period (T)=?(2) Amplitude (a)=?Given-V1=0.13 m/sWhenx1=0.12 mV2=0.12 m/swhenx2=0.13 m
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