An object located 1.07 cm in front of a spherical mirror forms an image located 10.5 cm behind the mirror. (a) What is the mirror's radius of curvature (in cm)? cm (b) What is the magnification of the image?
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Q: A convex spherical mirror, whose focal length has a magnitude of 15.2 cm, is to form an image 11.4…
A: Given data The focal length of the mirror is given as f = 15.2 cm. The image distance is given as v…
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Q: A concave mirror has a focal length of 37 cm. What is the position of the resulting image if the…
A: Solution:Given:f = focal length of concave mirror = -37 cmm = magnification of image = 1/5v = image…
Q: A doctor examines a mole with a 16.0 cm focal length magnifying glass held 13.0 cm from the mole.…
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Q: A convex spherical mirror, whose focal length has a magnitude of 16.4 cm, is to form an image 10.4…
A: focal length (f) of convex mirror = -16.4 cm image distance (i) = - 10.4 cm
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Q: A dental hygienist uses a small concave mirror to look at the back of a patient's tooth. If the…
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Q: You have a concave spherical mirror (the same holds if you had a convex mirror) If the value of q…
A: Given data: A concave mirror Image distance (q) = 1.86 m Object distance (p) = 3.7 m Required: The…
Q: An object is 66.0 cm from a concave mirror, and a real image forms 47.0 cm from the mirror. Find (a)…
A: Object distance, u = 66 cmImage distance, v = 47 cmFocal length, f = ? Magnification, m = ?
Q: virtual image is formed 21.0 cm from a concave mirror having a radius of curvature of 39.5 cm. (a)…
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Q: A convex (converging) lens produces a real, inverted image of an object that is magnified 2.30 times…
A: It is given that, the image produced by a convex lens is real and inverted. Let us say that the…
Q: You have a thin, diverging lens. If the value of q (the distance from the image to the mirror along…
A: Given : q = -3.15 cm p = 21.29 cm
Q: When viewed in a spherical mirror, the image of a setting sun is a virtual image. The image lies 12…
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Q: A photographer wishes to form a virtual image of a pearl at a distance of 17.6 cm behind a concave…
A: “Since you have posted a question with multiple sub-parts, we will solve first three subparts for…
Q: A virtual image is formed 24.0 cm from a concave mirror having a radius of curvature of 31.5 cm. (a)…
A: Given Image distance = 24.0 cm Image is virtual Radius of curvature = 31.5 cm We have to calculate…
Q: A double-convex thin lens is made of glass with an index of refraction of 1.55. The radii of…
A: Given, index of refraction =1.55 One glass radius = 57cm Secone glass radius = - 75cm We need to…
Q: A convex spherical mirror, whose focal length has a magnitude of 17.4 cm, is to form an image 11.2…
A: Focal length of mirror (f) = 17.4 cm Distance of image from mirror (v) = 11.2 cm
Q: A dentist uses a mirror to examine a tooth that is 1.00 cm in front of the mirror. The image of the…
A: a) The radius of the curvature, 1q+1p=2RR=2p·qp+qR=2×1×(6)1-(6)R=2.4cm
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Q: When viewed in a spherical mirror, the image of a setting sun is a virtual image. The image lies 15…
A: The mirror formula is given by 1v+1u =1f u = object distance v = image distance f = focal length
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A: Given, The object's distance from the mirror, u=-8.6 cm The image distance from the mirror, v=+32.0…
Q: A convex spherical mirror, whose focal length has a magnitude of 14.4 cm, is to form an image 10.6…
A: Given Information:- Magnitude of the focal length of the convex mirror is f=14.4 cm Image distance…
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A: Compound microscopes are used to get magnified images of tiny objects. It consists of two convex…
Q: A virtual image is formed 21.0 cm from a concave mirror having a radius of curvature of 39.5 cm. (a)…
A: The mirror formula is 1f=1v+1u…
Q: You have a concave spherical mirror (the same holds if you had a convex mirror) If the value of q…
A: Given:- the distance from the image to the mirror along the principal axis of the mirror is q=1.92 m…
Q: A virtual image is formed 21.5 cm from a concave mirror having a radius of curva (a) Find the…
A: (a)Consider the lens equation1f=1p+1q--------(1)herefocal length f=302=15 cmp=position of the object…
Q: When two lenses are used in combination, the first one forms an image that then serves as the object…
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Q: A convex spherical mirror, whose focal length has a magnitude of 15.2 cm, is to form an image 11.0…
A: Using mirror formula Where v = Image position, u = Object position, f = focal length of mirror…
Q: If a concave mirror has a focal length of 8.00 cm, how far from the mirror is the image of an object…
A: Given that,focal length, f=8 cmObject distance, x0=40 cm
Q: A convex mirror has a radius of curvature of 46.7 cm. A 11.5-cm-tall object is placed in front of…
A: Given, Radius of curvature = 46.7 cm Height of the objectho = 11.5 cm Height of the imagehi =…
Q: A concave mirror has a focal length of 39.3 cm. The distance between an object and its image is 66.8…
A: “Since you have posted a question with multiple sub parts, we willprovide the solution only to the…
Q: A doctor examine a mole length magnirying glass (a) Where is the image? (Enter the image distance in…
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Q: A spherical, concave shaving mirror has a radius of curvature of 0.476 m. What is the magnification…
A: Given data: Radius of curvature of the mirror: Object distance from the vertex of the mirror:…
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- Problem 7: Consider a makeup mirror that produces a magnification of 1.7 when a person’s face is 11.5 cm away. What is the focal length of the makeup mirror in meters?An object located 1.21 cm in front of a spherical mirror forms an image located 10.6 cm behind the mirror. (a) What is the mirror's radius of curvature (in cm)? cm (b) What is the magnification of the image? Need Help? Read ItA virtual image is formed 24.5 cm from a concave mirror having a radius of curvature of 39.5 cm. (a) Find the position of the object. cm in front of the mirror (b) What is the magnification of the mirror?
- The image behind a convex mirror (radius of curvature = 57.0 cm) is located 21.0 cm from the mirror. (a) Where is the object located (give the distance to the mirror) and (b) what is the magnification of the mirror? (a) Number i (b) Number i Units UnitsThe maximum magnification of a magnifying glass is m = 4.01×. What is its focal length in centimeters?An object is placed at a position in front of a spherical mirror such that and image is formed at a distance of 6.47 cm on the back side of the mirror. If the lateral magnification of the image is 2.52, what must the focal length of the mirror be?
- A concave spherical mirror has a radius of curvature, R = 18.2 cm. If an object is placed 53.4 cm in front of the lens, what is the magnification of the image produced?A doctor examines a mole with a 15.5 cm focal length magnifying glass held 11.5 cm from the mole. (a) Where is the image? (Enter the image distance in meters. Include the sign of the value in your answer.) m (b) What is its magnification? (c) How big in millimeters is the image of a 4.65 mm diameter mole? mmA concave mirror has the focal length equal to 0.609 m. To form a real image that is triple the size of the object on a screen, at what distance in front of the mirror should the screen be placed (in m; answer a positive number)?
- The image behind a convex mirror (radius of curvature-59.0 cm) is located 18.0 cm from the mirror. (a) Where is the object located (give the distance to the mirror) and (b) what is the magnification of the mirror? (a) Number (b) Number Units UnitsYou have a concave spherical mirror (the same holds if you had a convex mirror) If the value of q (the distance from the image to the mirror along the principal axis of the mirror) is 1.86m and the distance of p (the distance from the object to the mirror along the principal axis of the mirror) is 3.7m, what is the focal length of the mirror? P h A C B h' Q I k 9 P 1 The magnification equation and the sign convention for q imply that real images of real objects are always inverted (if both p and q are positive, m is negative); virtual images of real objects are always upright (if p is positive and q is negative, m is positive). Keeping the signs of p and q straight in your mind is the most challenging aspect of mirrors (and lenses). Fortunately, table 23.2 summarizes when p and q are positive and when they are negative.