An object is 11 mm from the objective of a certain compound microscope. The lenses are 277 mm apart and the intermediate image is 43.0 mm from the eyepiece. What overall magnification is produced by the instrument? Take the near point of the eye to be 25.0 cm. Number 123.36 Units TThis answer has no units

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Chapter1: Units, Trigonometry. And Vectors
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### Chapter 34, Problem 092

**Your answer is partially correct. Try again.**

An object is 11 mm from the objective of a certain compound microscope. The lenses are 277 mm apart and the intermediate image is 43.0 mm from the eyepiece. What overall magnification is produced by the instrument? Take the near point of the eye to be 25.0 cm.

Input Field:
- Number: 123.36 (Incorrect)

Units:
- Note: This answer has no units

---

In this problem, the solution requires the calculation of the overall magnification produced by a compound microscope. Relevant parameters include:
- Distance of the object from the objective lens (11 mm)
- Distance between the lenses (277 mm)
- Distance of the intermediate image from the eyepiece (43.0 mm)
- Near point of the eye (25.0 cm)

The indicated answer of 123.36 is only partially correct, and a different calculation or approach might be necessary to obtain the correct magnification value. No specific units are associated with the answer in this case.
Transcribed Image Text:### Chapter 34, Problem 092 **Your answer is partially correct. Try again.** An object is 11 mm from the objective of a certain compound microscope. The lenses are 277 mm apart and the intermediate image is 43.0 mm from the eyepiece. What overall magnification is produced by the instrument? Take the near point of the eye to be 25.0 cm. Input Field: - Number: 123.36 (Incorrect) Units: - Note: This answer has no units --- In this problem, the solution requires the calculation of the overall magnification produced by a compound microscope. Relevant parameters include: - Distance of the object from the objective lens (11 mm) - Distance between the lenses (277 mm) - Distance of the intermediate image from the eyepiece (43.0 mm) - Near point of the eye (25.0 cm) The indicated answer of 123.36 is only partially correct, and a different calculation or approach might be necessary to obtain the correct magnification value. No specific units are associated with the answer in this case.
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