Answered: An object in motion is accelerating a 4…

An object in motion is accelerating a 4 m/s2. At t = 1 s, the object is at positioned at +5 m, and is traveling at a velocity of 10 m/s. At t = 8 s, what is the position of the object? (xf)

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter2: Motion In One Dimension

Section: Chapter Questions

Problem 11P: A particle moves along the x axis according to the equation x = 2.00 + 3.00t 1.00t2, where x is in...

See similar textbooks

Related questions

Q: A particle’s velocity along the x-axis is described by v(t) = A t + B t2, where t is in seconds, v…

Q: A swimmer who can consistently keep the same pace to cover 50 meters in 8.41 seconds sets out to…

A: Given: Speed of current of river vrg=2.94 m/s Swimmer maintain pace to cover 50 m. in 8.41 s.

Q: A particle’s acceleration is (4.0iˆ+3.0jˆ)m/s2.(4.0i^+3.0j^)m/s2. At t = 0, its position and…

Q: A pirate ship launches a cannon ball with an initial speed of 200 m/s. The ball is to strike an…

Q: In 3.2 s, a particle moving with constant acceleration along the x axis goes from x = 31 m to x = 51…

A: Initial position of particle is, x0=31 m Final position of particle is, x=51 m Time taken by…

Q: A particle is moving along a straight line such that its acceleration is defined as a(v)= -6v m/s2,…

Q: An object moves in one dimensional motion with constant acceleration a = 4.5 m/s². At time t = 0 s,…

Q: At a time t = 0 s, an object is observed at position x = 0 m. Its position along the x axis is…

Q: A particle moves along the x axis according to the equation x = 2.07 + 2.98t − 1.00t2, where x is…

Q: A particle moves along the x axis according to the equation x = 1.90 + 3.02t − 1.00t2, where x is…

Q: A toy car starts at rest and accelerates up A 40ﾟ ramp with acceleration a=(t3)1/2. It then flies…

Q: A particle moving along the x-axis has its velocity described by the function v_x =2t2m/s=2t^2m/s,…

A: Given data: Velocity function of particle V = 2t2 m/s Initial position x0 = 2.8 m at t = 0 s

Q: the rocket starts from rest at t=0 and travel straight up. it's height above the ground as a…

Q: An object moves in one dimensional motion with constant acceleration a = 7.4 m/s². At time t = 0 s,…

Q: The coordinate of an object is given as a function of time by x(t) = 6t2 - t3, where x is in meters…

Q: 35. A person going for a walk follows the path shown in T Figure P3.35. The total trip consists of…

A: There are four displacement vectors. S1 = 100 i m S2 = - 270 j m S3 = -150 cos30 i - 150 sin30 j m…

Q: We are standing on the top of a 1040 feet tall building and launch a small object upward. The…

A: Given data The height of the building is H = 1040 ft. The expression for the height of the object…

Q: A computer model displays the motion of a particle on a coordinate system in real time. At time t =…

A: Velocity components: In x-direction, v = 0 In y-direction, v = 6.8 m/s Acceleration components: In…

Q: An object has an acceleration as a function of time given by (in m/s2): a = (7t2 + 2t) i + (5t3 +…

Q: time

Q: A particle moving along an x axis has an acceleration of 15.0 m/s2. At t = -2.0 s, the particle's…

A: Given that:- Acceleration of particle=15m/s^2

Q: The position of an object moving along an x axis is given by x = 3.18 t - 4.12 t2 + 1.01 t3, where x…

A: Distance is defined as the total length of the path traveled by an object in a specific time period.…

Q: The velocity of an object as a function of time is given by v=3t2+5t-12 m/s, where t is in seconds.…

Q: The position of a squirrel running in a park is given by r⃗ =[(0.280m/s)t+(0.0360m/s2)t2]i^+…

A: The position of the squirrel is given by

Q: a particle is moving along a straight such that its acceleration is defined as v^2=k/x m/s, where k…

Q: An object moves in along the x-axis with an acceleration given by: a = 9t (m/s2). The position of…

Q: The position of a particle moving along the x axis is given by x = (10 +5t…

A: To calculate the velocity we must differentiate position with respect to time. we have been given…

Q: A helicopter starts ascending in the sky from the ground and its position is given by y = 5t^2 +…

Q: a particle moves in one dimension, and its position as a function of time is given by x = (1.9m/s)t…

Q: the acceleration a versus time t for a particle moving along an x axis. the a-axis scale is set by…

A: Given Data: The acceleration of the particle is: as=12 m/s2 The time of the given acceleration is:…

Q: A helicopter starts ascending in the sky from the ground and its position is given by 5t2 + 10t.…

A: Given, Position y=5t2+10t

Q: A particle’s acceleration is (4.0 i+3.0 j) m/s2. At t=0, its position and velocity are zero. (a)…

Concept explainers

Distance and Speed

The speed, distance and time relation forms the basis of study of motion. You will need these concepts in the study of Mechanics. This concept is applicable for students who are studying the following courses –

Question

An object in motion is accelerating a 4 m/s2. At t = 1 s, the object is at positioned at
+5 m, and is traveling at a velocity of 10 m/s. At t = 8 s, what is the position of the
object? (xf)
%3D
%3D
124 m
271 m
467 m
173 m

Expert Solution

Step 1 given

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

One drop of oil falls straight down onto the road from the engine of a moving car every 5 s. Figure OQ2.1 shows the pattern of the drops left behind on the pavement. What is the average speed of the car over this section of its motion? (a) 20 m/s (b) 24 m/s (c) 30 m/s (d) 100 m/s (e) 120 m/s Figure OQ2.1
The position of a particle moving along the x axis varies in time according to the expression x = 3t2, where x is in meters and t is in seconds. Evaluate its position (a) at t = 3.00 s and (b) at 3.00 s + t. (c) Evaluate the limit of x/t as t approaches zero to find the velocity at t = 3.00 s.
One drop of oil falls straight down onto the road from the engine of a moving car every 5 s. Figure OQ2.1 shows the pattern of the drops left behind on the pavement. What is the average speed of the car over tins section of its motion? (a) 20 m/s (b) 24 m/s (c) .30 m/s (d) 100 m/s (e) 120 m/s
35. A person going for a walk follows the path shown in T Figure P3.35. The total trip consists of four straight-line paths. At the end of the walk, what is the person's resultant displacement measured from the starting point? Start 100 m 300 m End 200 m 30.0 150 m 60.0° Figure P3.35
We are standing on the top of a 1040 feet tall building and launch a small object upward. The object's height, measured in feet, after t seconds is h(t) = 16t? + 128t + 1040. A) What is the object initial velocity? ft/second B) What is the highest point that the object reaches? feet
The coordinate of an object is given as a function of time by x(t) = 6t2 – t3, where x is in meters and t is in seconds. What is the position of the particle when it achieves its maximum speed? %3D Option 1 Option 2 Option 3 Option 4 Option 5 18 m 14 m 16 m 12 m 10 m
An object moves in along the x-axis with an acceleration given by: a = 9t (m/s2). The position of the object at t=0.0 is 5 m, and its velocity at t=0.0 s is 7 m/s. Calculate the position at t=8 s.
An object moves in one dimensional motion with constant acceleration a = 4.5 m/s². At time t = 0 s, the object is at xo = 2.9 m and has an initial velocity of vo = 4 m/s. How far will the object move before it achieves a velocity of v = 7 m/s? Your answer should be accurate to the nearest 0.1 m.
An object moves in along the x-axis with an acceleration given by: a = 5t2 + 10t (m/s2). The velocity at t=0.0 s is 3 m/s. Calculate the velocity at t=7 s.
A particle moves along the x axis according to the equation x = 2.07 + 2.98t − 1.00t2, where x is in meters and t is in seconds. (a) Find the position of the particle at t = 2.60 s. m(b) Find its velocity at t = 2.60 s. m/s(c) Find its acceleration at t = 2.60 s. m/s2
The flight path of the particle as it takes off from A is defined by the parametric equations x=(21²) m and y=(0.04t³) m, where t is the time in seconds. Determine the magnitude of its acceleration when t = 15 S. O 3.85 m/s² O 5.38 m/s2 O 5.83 m/s² 8,35 m/s²
A particle moves along the x axis according to the equation x = 1.90 + 3.02t − 1.00t2, where x is in meters and t is in seconds. (a) Find the position of the particle at t = 2.50 s. in m(b) Find its velocity at t = 2.50 s. in m/s(c) Find its acceleration at t = 2.50 s.in m/s2