An object creates an electric field that points towards it. At 5.5 cm the E field strength is 138,383 N/C. What is the object's charge in nC?
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Q: What
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Q: 5.0−μC charge experiences a 0.41-N force in the positive y direction. a. If this charge is replaced…
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A: Given data :- charge q = 4.5 C (magnitude of the given charge) electric field E = 66079 N/C
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Q: An electric field E = 180000 i N/C causes the point charge of q = 17 nC to hang at an angle θ (see…
A: Given data: Electric field (E) = 180000 i N/C Charge (q) = 17 nC = 17 × 10-9 C Mass of the charge…
Q: A -65.1 MicroC charge is in a 23648 N/C electric field. What is the magnitude of the force (in N) on…
A: Given data: Charge (q) = -65.1 μC = -65.1×10-6 C Electric field (E) = 23648 N/C Required: The…
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- Part A: A foam block that contains a charge of 0.0054 coulombs (C) experiences an electrostatic force of 8 newtons (N) from a foam ball 30 centimeters (cm) away. How much charge is on the ball? Part B: Create a question about a foam ball experiencing 224 newtons of force that uses Newton's Third Law of Motion to answer it. Then answer it. Part C: A typical bolt of lightning carries billions of joules (1 GJ = 109 J) of energy, but discharges it over a very short period of time. If a particular lightning bolt discharges 8 GJ of energy in 30 microseconds (1 µs = 10-6 s), then how many watts (W) of power did it deliver? Express your answer in scientific notation.A 13.0 nC charge is located at × =0 m. Calculate the electric field of that charge atV= 10.0 m. If we would put a negatively charge particle - q=19.0 nC at that location, How muchelectrical force that particle would experience? If the mass of the particle is 10.0 x10^-6 kg. What would be the magnitude anddirection of its acceleration?For each charge distribution: -6.0 x 10-5 C 4.0 x 10-5 C 2.0 m 9₁ L. - 6.0 x 10-5 C 3.0 m A q2 2.0 m A 3.0 m 2 - 3.0 x 10-5 C 1. 2. a. Determine the net electric field at point A for the following charge distribution. b. The magnitude of the electric field due to each charge, (i.e. calculate ε₁ and ε2), at point A. c. The net electric field at point A. a. For each part in practice question 1, find the net force on a -1.2 × 10-5 C charge placed at point A. b. How would your answer change if the sign of the charge from 2a at point A was changed? 3. Explain why the concept of a field was used to describe the force of gravity between two masses. 4. Give two reasons why the concept of a field is used again to describe the force between two charged objects.
- 34. Figure P15.34 shows the electric field lines for two point charges separated by a small distance. a. Determine the ratio 91/92. b. What are the signs of q₁ and 92? Figure P15.34 92 91A 6.6-μC charge is placed at the origin and a second charge is placed on the x-axis at x = 0.1 m. If the resulting force on the second charge is 5.7 N in the positive x-direction, what is the value of its charge? a. 1.0 μC b. 1.0 nC c. –1.0 μC d. –1.0 nC e. 0 μCP6E4
- A proton is released in a uniform electric field, and it experiences an electric force of 2.31×10−14 NN toward the south. A.What is the magnitude of the electric field? B. What is the direction of the electric field? north south west eastTwo 10-cm-diameter charged rings face each other, 15.0 cm apart. Both rings are charged to +50.0 nC. What is the electric field strengthWhat is the electric field at a distance of 75 cm from a 30 nC charge? O 760 N/C O 1000 N/C 2800 N/C 480 N/C 850 N/C