An MRI technician moves his hand from a region of very low magnetic field strength into an MRI scanner's 2.00-T field with his fingers pointing in the direction of the field.(a) Find the average emf induced in his wedding ring, given its diameter is 2.23 cm and assuming it takes 0.254 s to move it into the field.3.35What is the magnitude of the change in flux? How is the induced emf related to the change in flux? mv(b) If the resistance of the ring is 1.00 mn, how much heat will be transferred to the ring during this time?2.84How much power is associated with this emf? How is energy related to power? m)

When a conductor is kept in a varying magnetic field the change in magnetic flux will induce a voltage on the conductor. This induced voltage is called induced electromotive force. It is given by, ε=dϕdt Here ϕ is the magnetic flux. Magnetic flux is given by, ϕ=BA Here, B is the magnetic field strength and A is the area.Induced emf can be written as, ε=dϕdt=ϕf-ϕitf-ti Take initial time and magnetic flux is zero. ε=ϕftf Now, ε=B×Atf=B(πD2)4tf Now, substitute B as 2.00 T, D as 2.23 cm, and tf as 0.254 s. ε=(2.00 T)(π(2.23×10-2 m)2)4(0.254 s)=0.003075 Vε=3.075 mVNow for calculating thermal energy we first need power, P=V2R=3.075×10-3 V1.00×10-3 Ω=3.075 W Now heat energy will be, E=Pt=(3.075 W)(0.254 s)=0.781 JE=0.781 J

Answered: An MRI technician moves his hand from a…