An investor is looking at the performance of a particular investment andthe information is provided in the table below :Periods Return %19.024.53.-6.24-5.62.510.67-6.981.54.6103.4Required:1. Calculate the mean.2. Calculate standard deviation using the table method.3. Construct a 99% confidence interval estimate of the populationmean return of the investment4. Do you think that the advisor has the right to state that theportfolio will reap a return of 8%5. Must you assume that the population of return is normallydistributed? Explain your answer[Hint : Answer to one decimal place]

Answered: Image /qna-images/answer/213610ae-752a-42cd-a064-41fb7283354e.jpg

Answered: An investor is looking at the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Chapter 3 271 Forecast (X) Number of Analysts (n;) 1.40 1 1.43 1.44 1.45 2 1.47 1 1.48 1.50 Because the sample is a small fraction of the number of analysts who follow this stock, assume that we can ignore the finite population correction factor. Assume that the analyst forecasts are normally distributed. A. What are the mean forecast and standard deviation of forecasts? B. Provide a 95 percent confidence interval for the population mean of the forecasts.
True or false? If the original x distribution has a relatively small standard deviation, the confidence interval for ? will be relatively short. a. False. As ? decreases, E decreases, resulting in a longer confidence interval. b. True. As ? decreases, E increases, resulting in a shorter confidence interval. c. True. As ? decreases, E decreases, resulting in a shorter confidence interval. e. False. As ? decreases, E increases, resulting in a longer confidence interval.
For table 3, determine the following point estimates: 1. The mathematical expectation. 2. The variance. 3. The root mean square deviation 4. Correlation coefficient between X and Z
Expected returns and standard deviations have been calculated for five projects. Rank them in terms of total risk, from highest risk to lowest risk. std deviation Project A B C D E O DACBE O AEDCB O EDBCA O ACEBD O none of these E(R) 5.9% 12.3% 8.4% 14.9% 16.2% 1.8% 2.5% 2.3% 2.9% 3.3%
Risk taking is an important part of investing. In order to make suitable investment decisions on behalf of their customers, portfolio managers give a questionnaire to new customers to measure their desire to take financial risks. The scores on the questionnaire are approximately normally distributed with a mean of 50 and a standard deviation of 14. The customers with scores in the bottom 15% are described as "risk averse." What is the questionnaire score that separates customers who are considered risk averse from those who are not? Carry your intermediate computations to at least four decimal places. Round your answer to one decimal place.
Exercise 3. A personal manager has found that historically the scores on aptitude tests given to applicants for entry-level positions follow a normal distribution with a standard deviation of 32.4 points. A random sample of nine test scores from the current group of applicants had a mean score of 187.9 points. a. Find an 80% confidence interval for the population mean score of the current group of applicants. b. Based on these sample results a statistician found for the population mean a confidence interval extending from 165.8 to 210.0 points. Find the confidence level of this interval.
Data set is on picture #2
A company that develops an automated customer service model is interested in knowing whether two versions, Version A and Version B, will get different ratings from customers. Participants in a focus group are taken through samples from both versions, then take a survey to rate each version. A summary of the data obtained from the study is given below. Assume ratings from the different surveys generally have the same standard deviation. Mean Observations Pearson Correlation Hypothesized Mean Difference df t Stat P(T<=t) one-tail t Critical one-tail P(T<=t) two-tail t Critical two-tail Confidence Level Version A Version B 33.133 28.67 15 15 -0.325 0.00 14 n = Ex: 9 -1.426 0.088 -1.345 0.176 -1.761 95% Degrees of freedom: df Point estimate for Version A: XA = Ex: 1.234 Point estimate for Version B: x B = 1 = من t = −1 Ex: 1.234 0 1 t = P = = Ex: 1.234 2 3 2
Energy drinks: A survey of college students reported that in a sample of 402 male college students, the average number of energy drinks consumed per month was 2.41 with a standard deviation of 3.18, and in a sample of 390 female college students, the average was 1.50 with a standard deviation of 4.77. Part: 0/2 Part 1 of 2 Construct a 80% confidence interval for the difference between men and women in the mean number of energy drinks consumed. Let μ, denote the mean number of energy drinks consumed by men. Use tables to find the critical value and round the answers to at least two decimal places. A 80% confidence interval for the difference between men and women in the mean number of energy drinks consumed is 0<44-₂2 <0. X S Part: 1/2 Part 2 of 2 Based on the confidence interval, is it reasonable to believe that the mean number of energy drinks consumed may be the same for both male and female college students? It (Choose one) reasonable to believe that the mean number of energy drinks…
The average amount of money spent by an Amazon customer per month is $1296 with standard deviation $110. Assume the variable is normally distributed. Answer the following questions. What is the probability that a random sample of 15 Amazon customers spent an average between $1100 and $1300 in a month?
Summary statistics for Chol: (a) Calculate a 95% confidence interval (Chapter 17) for the mean Cholesterol of heart disease patients. Use the t-distribution table and the Cholesterol summary statistics.Group by: HD HD n Mean Variance Std. dev. Std. err. Median Range Min Max Q1 Q3 No 164 242.64024 2857.606 53.45658 4.1742576 234.5 438 126 564 208.5 267.5 Yes 139 251.47482 2448.9468 49.486835 4.1974185 249 278 131 409 217 284

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