An insurance company offers its policyholders a number of different premium payment options. For a randomly selected policyholder, let X = the number of months between successive payments. The cdf of X is as follows: x < 1 0.38 1sx< 3 J0.48 3 Sx< 4 F(x) = 0.53 4 Sx< 6 0.87 6 SX< 12 12 sx (a) What is the pmf of X? 1 3 6 12 P(x) (b) Using just the cdf, compute P(3 SXS 6) and P(4 S X). P(3 SXS 6) = P(4 S X) =
An insurance company offers its policyholders a number of different premium payment options. For a randomly selected policyholder, let X = the number of months between successive payments. The cdf of X is as follows: x < 1 0.38 1sx< 3 J0.48 3 Sx< 4 F(x) = 0.53 4 Sx< 6 0.87 6 SX< 12 12 sx (a) What is the pmf of X? 1 3 6 12 P(x) (b) Using just the cdf, compute P(3 SXS 6) and P(4 S X). P(3 SXS 6) = P(4 S X) =
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Transcribed Image Text:An insurance company offers its policyholders a number of different premium payment options. For a randomly selected policyholder, let X = the number of months between successive payments. The cdf of X is as follows:
x < 1
13x< 3
3 <x < 4
4 <x < 6
0.38
0.48
F(x) =
0.53
0.87
6 Sx< 12
1
12 <x
(a) What is the pmf of X?
1
3
6
12
P(x)
(b) Using just the cdf, compute P(3 < XS 6) and P(4 s X).
P(3 S XS 6) =
P(4 s X) =
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