An insurance company offers its policyholders a number of different premium payment options. For a randomly selected policyholder, let X = the number of months between successive payments. The cdf of X is as follows: x < 1 0.38 1sx< 3 J0.48 3 Sx< 4 F(x) = 0.53 4 Sx< 6 0.87 6 SX< 12 12 sx (a) What is the pmf of X? 1 3 6 12 P(x) (b) Using just the cdf, compute P(3 SXS 6) and P(4 S X). P(3 SXS 6) = P(4 S X) =

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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An insurance company offers its policyholders a number of different premium payment options. For a randomly selected policyholder, let X = the number of months between successive payments. The cdf of X is as follows:
x < 1
13x< 3
3 <x < 4
4 <x < 6
0.38
0.48
F(x) =
0.53
0.87
6 Sx< 12
1
12 <x
(a) What is the pmf of X?
1
3
6
12
P(x)
(b) Using just the cdf, compute P(3 < XS 6) and P(4 s X).
P(3 S XS 6) =
P(4 s X) =
Transcribed Image Text:An insurance company offers its policyholders a number of different premium payment options. For a randomly selected policyholder, let X = the number of months between successive payments. The cdf of X is as follows: x < 1 13x< 3 3 <x < 4 4 <x < 6 0.38 0.48 F(x) = 0.53 0.87 6 Sx< 12 1 12 <x (a) What is the pmf of X? 1 3 6 12 P(x) (b) Using just the cdf, compute P(3 < XS 6) and P(4 s X). P(3 S XS 6) = P(4 s X) =
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