An inertial frame of reference is one in which the ______________________ is zero. fill in the blank
Q: Far in space, where gravity is negligible, a 425 kg rocket traveling at 95 m/s fires its engines.…
A: Far in space, where gravity is negligible,Mass of rocket M = 425 kgVelocity of rocket =95 m/sAlso…
Q: Assume your weight 121 lbs (a) Compute your weight in n (b) Compute your mass in kg. Compute your…
A: Weight in lbs = 121 lbsNeed to find mass in kg , in slug and weight in Newton.
Q: Sphere A with mass 80 kg is located at the origin of an xy coordinate system; sphere B with mass 60…
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Q: The mass of Jupiter is 1.88x1027 kg and its radius is 7.18x107 m. Find the acceleration due to…
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Q: (a) Find the magnitude of the gravitational force (in N) between a planet with mass 7.75 ✕ 1024 kg…
A: Write the given values with suitable variables. M=7.75×1024 kgm=2.75×1022 kgr=2.9×108 m Here, M, m,…
Q: You have been assigned to a team charged with developing a plan to explore a new planetary body…
A: Given g=2.8 m/s2 specific gravity of oil=0.93 weight of oil=4 lbf
Q: According to this law, force of attraction from larger on smaller mass is r m M O Equal to the force…
A: Given , Mathematically the force of attraction between two objects of masses M and m is given as…
Q: Consider Kepler's equation regarding planetary orbits, given as M = E e sin(E), where M is the mean…
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Q: A)Find the magnitude of the gravitational force (in N) between a planet with mass 8.75 ✕ 1024 kg and…
A: It is given that, mp=8.75×1024 kgmm=2.30×1022 kgr=2.40×108 m
Q: The radius of a planet is three times that of Earth and its mass is nine times that of Earth. The…
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Q: A cube of tin with sides of length 2.8 m is transported to the surface of Mars. What is the weight…
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Q: Problem: According to Newton’s law of gravitation, what is the magnitude of the force between the…
A: Mass of the Earth , m = 5.97×1024 kg Mass of the Sun , M = 2.00×1030 kg Distance between Earth and…
Q: A planet has an equatorial radius of 5.39 × 107 m and a mass of 6.71 × 1026 kg. (a) Compute the…
A: Given that: R=5.39×107 mM=6.71×1026 Kg here, it is required to determine the acceleration due to…
Q: At what altitude h above the north pole is the weight of an object reduced to 27% of its…
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Q: Astronomical observations of our Milky Way galaxy indicate that it has a mass of about 8.0 • 1011…
A: Given: M= 8 x 1011 solar mass r=6 x 104 light years T= 6 x 107 years
Q: Newton's universal law of gravitation states that every particle in the universe attracts every…
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Q: Find the magnitude of the gravitational force between a planet with mass of 7.97x1024 kg and its…
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Q: Assume that planet A has radius RA and mass MA, and planet B has radius Rg and mass Mg. Let ga and…
A: radius of planet A=RAmass of planet A=MAradius of planet B=RBmass of planet B=MB
Q: Two planets of equal mass orbit a certain star. The planet Iang (m1) describes a circular orbit of…
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Q: Sphere A with mass 89 kg is located at the origin of an xy coordinate system; sphere B with mass 58…
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Q: Two treads balls with masses 2 kilogram and three kilograms are suspended on threads of 70…
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Q: Four masses 2.8 kg each, are positioned at the corners of an square with side 2.8 m. Determine the x…
A: The gravitational force acting between the two masses M and m is calculated by using the formula…
Q: Sphere A with mass 70 kg is located at the origin of an xy coordinate system; sphere B with mass 73…
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Q: (a) Find the magnitude of the gravitational force (in N) between a planet with mass 8.00 ✕ 1024 kg…
A: Given data: Mass of the planet (M1) = 8.00×1024 kg Mass of the moon (M2) = 2.50×1022 kg Distance…
Q: Find the magnitude of the gravitational force (in N) between a planet with mass 7.00 ✕ 1024 kg and…
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Q: he earth’s mass is 5.972x1024 kgs and the earth’s radius is 6371 kms, determine the altitude of a…
A: Given: M=5.972*1024 kgR=6371 km = 6.371*106 mgh=9.7 m/s2
Q: the earth, what are the magnitude and direction of the force the object exerts on Ihe 10.If an…
A: According to Newton's third law Every action has equal and opposite reaction.
Q: n the year 25 000 the Earth is 1.42x1011 m away from the sun and in a circular orbit, but a year…
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Q: The equatorial radius of the Earth is 6378 km and gravity at the equator is 9.780 m s-2. Compute the…
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Q: A woman whose weight is 680 N on the Earth’s surface is in a spacecraft at an altitude above the…
A: Weight, W = 680 N Weight in the spacecraft, W' = ?
Q: a)find the magnitude of the gravitational force (in N) between a planet with mass 9.00 ✕ 1024 kg and…
A: Ans: Given: Mass of planet m1=9.00 ✕ 10²⁴ kg Mass of moon m2=2.20 ✕ 10²² kg Separation between…
Q: How can I explain the small percent difference/error between my experimental result and the accepted…
A: Write the expression for percentage error.
Q: Newton's law of universal gravitation states that two particles exert a pull on each other with…
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Q: The mass of Jupiter is 1.88x1027 kg and its radius is 7.18x107 m. Find the acceleration due to…
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Q: When the Moon is directly overhead at sunset, the force by Earth on the Moon, FEM, is essentially at…
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- While doing an experiment a student uses a triple beam balance to measure the mass of a cart and gets 273.9 g. While calculating the mass they get the values: 268.5 g. 288.7 g, and 270 g. What would the GAV for the cart be? 268.5 g 288.7 g 275.7 g 274.8 g 273.9 gA planet has a mass of 6.90 × 1023 kg and a radius of 2.89 × 106 m. (a) What is the acceleration due to gravity on this planet? (b) How much would a 74.8-kg person weigh on this planet?If the earth has a period of 9.94x1014 seconds and the mass of the sun is 1.989 x1030 kg, find the distance between these two bodies.
- We will use differential equations to model the orbits and locations of Earth, Mars, and the spacecraft using Newton’s two laws mentioned above. Newton’s second law of motion in vector form is: F^→=ma^→ (1) where F^→ is the force vector in N (Newtons), and a^→ is the acceleration vector in m/s^2,and m is the mass in kg. Newton’s law of gravitation in vector form is: F^→=GMm/lr^→l*r^→/lr^→l where G=6.67x10^-11 m^3/s^2*kg is the universal gravitational constant, M is the mass of the larger object (the Sun), and is 2x10^30 kg, and m is the mass the smaller one (the planets or the spacecraft). The vector r^→ is the vector connecting the Sun to the orbiting objects. Step one ) The motion force in Equation(1), and the gravitational force in Equation(2) are equal. Equate the right hand sides of equations (1) and (2), and cancel the common factor on the left and right sides. Answer: f^→=ma^→ f=Gmm/lr^→l^2 a^→=Gmm/lr^→l^2 x r^→/lr^→l r^→=r^→/lr^→l * Gmm Could you please…On Earth, a person has a weight of 520 N. What weight would the person have on Mars? Theradius of Mars is 53% of the radius of Earth, and its mass is 11% of the mass of Earth.Please asap
- A 750-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth's mean radius. (a) Find the satellite's orbital speed. 1768.95 × Your response differs from the correct answer by more than 10%. Double check your calculations. m/s (b) Find the period of its revolution. 12.576 Your response differs from the correct answer by more than 100%. h (c) Find the gravitational force acting on it. 114.11 × Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. NThe planet jupiter is roughly 318 times more massive than the planet earth, and it orbits at an average radius of 5.24 times the orbital radius of the earth. Assuming circular motion of both planets about the sun, find: (a) The ratio of the gravitational forces Fe and Fj on the planets due to the sun. (b) Find the ratio of the orbital periods TE to Tj (c) How long is Jupiter's year, measured in earth yearsThe planet, named 581 c that has a radius that is 1.5 times the radius of Earth. If the acceleration of the gravity on the surface of the planet 581 c, g 581c = 2.22 g Earth. Find the mass of the planet 581 c.