An industrial electric motor has a load of 900 kW at 0.75 power factor lag. It is used for 500 hours in a year. The tariff for electricity supply to this industry is based on an annual maximum (KVA) demand of Rs. 120 and per unit consumption Rs. is 0.6. A phase advancing plant has been set up to improve the power factor of this load to 0.9837. The cost per kVA of the plant is Rs. 75 / – + 12% of the plant investment. Calculate the following: (1) Phase advancing plant capacity (kVA) (2) Energy cost savings from improving power factor
An industrial electric motor has a load of 900 kW at 0.75 power factor lag. It is used for 500 hours in a year. The tariff for electricity supply to this industry is based on an annual maximum (KVA) demand of Rs. 120 and per unit consumption Rs. is 0.6. A phase advancing plant has been set up to improve the power factor of this load to 0.9837. The cost per kVA of the plant is Rs. 75 / – + 12% of the plant investment. Calculate the following: (1) Phase advancing plant capacity (kVA) (2) Energy cost savings from improving power factor
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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An industrial electric motor has a load of 900 kW at 0.75 power factor lag. It is used for 500 hours in a year. The tariff for electricity supply to this industry is based on an annual maximum (KVA) demand of Rs. 120 and per unit consumption Rs. is 0.6. A phase advancing plant has been set up to improve the power factor of this load to 0.9837. The cost per kVA of the plant is Rs. 75 / – + 12% of the plant investment. Calculate the following: (1) Phase advancing plant capacity (kVA) (2) Energy cost savings from improving power factor
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