An inductor with L = 9.5 H is in a closed circuit with I= 0.45 A (see the diagram). When the switch is opened, the current goes to zero in At = 0.16 s. L= 9.5 H L I= 0.45 A At = 0.16 s I (a) Express the magnitude of the average induced emf on the inductor, ɛave, in term Eave = (b) Calculate the numerical value of ɛave in volts. Eave =
An inductor with L = 9.5 H is in a closed circuit with I= 0.45 A (see the diagram). When the switch is opened, the current goes to zero in At = 0.16 s. L= 9.5 H L I= 0.45 A At = 0.16 s I (a) Express the magnitude of the average induced emf on the inductor, ɛave, in term Eave = (b) Calculate the numerical value of ɛave in volts. Eave =
Related questions
Question
100%
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 1 images