An inductor with L = 9.5 H is in a closed circuit with I= 0.45 A (see the diagram). When the switch is opened, the current goes to zero in At = 0.16 s. L= 9.5 H L I= 0.45 A At = 0.16 s I (a) Express the magnitude of the average induced emf on the inductor, ɛave, in term Eave = (b) Calculate the numerical value of ɛave in volts. Eave =
An inductor with L = 9.5 H is in a closed circuit with I= 0.45 A (see the diagram). When the switch is opened, the current goes to zero in At = 0.16 s. L= 9.5 H L I= 0.45 A At = 0.16 s I (a) Express the magnitude of the average induced emf on the inductor, ɛave, in term Eave = (b) Calculate the numerical value of ɛave in volts. Eave =
Related questions
Question
100%

Transcribed Image Text:An inductor with L = 9.5 H is in a closed circuit with I= 0.45 A (see the diagram).
When the switch is opened, the current goes to zero in At = 0.16 s.
L= 9.5 H
L
I= 0.45 A
At = 0.16 s
I
(a) Express the magnitude of the average induced emf on the inductor, ɛave, in terms of L, I and At.
Eave =
(b) Calculate the numerical value of ɛave in volts.
Eave =
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 1 images
