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An inductor with inductance L = 0.500 H and negligible resistance is connected to a battery, a switch S, and two resistors, R₁ = 8.00 2 and R₂ = 4.00 2 (Figure 1). The battery has emf 48.0 V and negligible internal resistance. S is closed at t = 0. Figure < 1 of 1 > An inductor with inductance L = 0.5 H and negligible resistance is connected to a battery, a switch S, and two resistors, R₁ = 8.00 2 and R₂ = 4.00 S2 (Figure 1). The battery has emf 48.0 V and negligible internal resistance. S is closed at t=0. Apply Kirchhoffs rules to the circuit and obtain a differential equation for i3 (t). Integrate the equation to obtain an equation for i3 as a function of the time t that has elapsed since S' was closed. Express your answer in terms of the variables R₁, R2, L, E, and t. xa E t= L Submit —| ΑΣΦ Xb Submit 99 Value √x √√x x templates fraction Previous Answers Request Answer Part H Use the equation that you derived in part G to calculate the value of t for which i3 has half of the final value that you calculate in part F Express your answer with the appropriate units. Request Answer Units ? ? X.10n

An inductor with inductance L = 0.500 H and negligible resistance is connected to a battery, a switch S, and two resistors, R₁ = 8.00 2 and R₂ = 4.00 2 (Figure 1). The battery has emf 48.0 V and negligible internal resistance. S is closed at t = 0. Figure < 1 of 1 > An inductor with inductance L = 0.5 H and negligible resistance is connected to a battery, a switch S, and two resistors, R₁ = 8.00 2 and R₂ = 4.00 S2 (Figure 1). The battery has emf 48.0 V and negligible internal resistance. S is closed at t=0. Apply Kirchhoffs rules to the circuit and obtain a differential equation for i3 (t). Integrate the equation to obtain an equation for i3 as a function of the time t that has elapsed since S' was closed. Express your answer in terms of the variables R₁, R2, L, E, and t. xa E t= L Submit —| ΑΣΦ Xb Submit 99 Value √x √√x x templates fraction Previous Answers Request Answer Part H Use the equation that you derived in part G to calculate the value of t for which i3 has half of the final value that you calculate in part F Express your answer with the appropriate units. Request Answer Units ? ? X.10n

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Solve Part G and H
An inductor with inductance L = 0.500 H and negligible resistance is connected to a battery, a switch S, and two resistors, R₁ = 8.00 2 and R₂ = 4.00 S2 (Figure 1). The battery has emf 48.0 V and negligible internal resistance. S is closed at t = 0. Figure < 1 of 1 An inductor with inductance L = 0.500 H and negligible resistance is connected to a battery, a switch S, and two resistors, R₁ = 8.00 2 and R₂ = 4.00 S2 (Figure 1). The battery has emf 48.0 V and negligible internal resistance. S is closed at t=0. Figure 1 of 1 www R₁ O R₂ L > Part G Apply Kirchhoffs rules to the circuit and obtain a differential equation for i3 (t). Integrate the equation to obtain an equation for i3 as a function of the time t that has elapsed since S was closed. Express your answer in terms of the variables R₁, R2, L, E, and t. iz = [5] ΑΣΦ xa E L Submit Xh •t √x √x x μÀ templates fraction Previous Answers Request Answer t= Value x Submit Request Answer Units Part H Use the equation that you derived in part G to calculate the value of t for which i3 has half of the final value that you calculated in part F. Express your answer with the appropriate units. IXI ? ? X 10n X
Transcribed Image Text:An inductor with inductance L = 0.500 H and negligible resistance is connected to a battery, a switch S, and two resistors, R₁ = 8.00 2 and R₂ = 4.00 S2 (Figure 1). The battery has emf 48.0 V and negligible internal resistance. S is closed at t = 0. Figure < 1 of 1 An inductor with inductance L = 0.500 H and negligible resistance is connected to a battery, a switch S, and two resistors, R₁ = 8.00 2 and R₂ = 4.00 S2 (Figure 1). The battery has emf 48.0 V and negligible internal resistance. S is closed at t=0. Figure 1 of 1 www R₁ O R₂ L > Part G Apply Kirchhoffs rules to the circuit and obtain a differential equation for i3 (t). Integrate the equation to obtain an equation for i3 as a function of the time t that has elapsed since S was closed. Express your answer in terms of the variables R₁, R2, L, E, and t. iz = [5] ΑΣΦ xa E L Submit Xh •t √x √x x μÀ templates fraction Previous Answers Request Answer t= Value x Submit Request Answer Units Part H Use the equation that you derived in part G to calculate the value of t for which i3 has half of the final value that you calculated in part F. Express your answer with the appropriate units. IXI ? ? X 10n X
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