An independent-measures research study uses two samples, each with n = 12, to compare two treatments using a pooled procedure. If the results are evaluated with a t statistic using a one-tailed test with a = .01, then the critical region would have the following boundary. Ot= 2.797 Ot = 2.492 Ot- 2.508 Ot = 2.819
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- A repeated-measures analysis of variance for a study comparing three treatment conditions with a sample of n = 20 participants, produces an F-ratio of F = 6.10. For this result, which of the following is the correct statistical decision? a. Fail to reject the null hypothesis with either a = .05 or a = .01 b. Reject the null hypothesis with a = .05 but not with a = .01 c. There is not enough information to determine the correct decision. d. Reject the null hypothesis with either a = .05 or a = .01Dr. Graham is interested in determining if middle-aged adults use text messaging more or less frequently than the general population. Dr. Graham collects information on text messaging from a random sample of 50 adults ages 25 to 44. Dr. Graham finds that these individuals send or receive an average of 68 text messages per day. Using the population mean (and standard deviation) of 41.5 texts per day (34 texts per day), determine whether adults in this age group use text messaging more than the general public.Using traditional methods it takes 8.2 hours to receive a basic flying license. A new license training method using Computer Aided Instruction (CAI) has been proposed. A researcher used the technique on 26 students and observed that they had a mean of 8.0 hours with a variance of 2.89. Is there evidence at the 0.1 level that the technique reduces the training time? Assume the population distribution is approximately normal. Step 3 of 5: Specify if the test is one-tailed or two-tailed.
- An engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such that it would produce a mean pressure of 5.5 pounds/square inch. It is believed that the valve performs above the specifications. The valve was tested on 24 engines and the mean pressure was 5.7 pounds/square inch with a variance of 0.49. A level of significance of 0.01 will be used. Assume the population distribution is approximately normal. Make the decision to reject or fail to reject the null hypothesis.A company with a large fleet of cars hopes to keep gasoline cost down and sets a goal of attaining a fleet average of greater than 26 miles per gallon. To see if their goal is being met, they check the gasoline usage of 50 company trips, finding a mean of 27.01 miles per gallon. Define the relevant parameter, state the null and alternative hypothesis, and test at the 5% significance level to see whether this sample provides evidence that the company is meeting its goal. The standard error from the randomization distribution under the null hypothesis is SE = 0.68.Is the following statment true or false? Why? The p-value was obtained using the t-distribution table. The sample sizes of the two groups were 33 and 22, and the degree of freedom was 53. To find the p-value, it is necessary to look at the row corresponding to 53 at a significance level of 0.05 and two tails. The value of the critical test statistic is 2. The computed t-statistic, 0.2112, falls between 0 and 0.679 from the same row. The next step is to look at the alpha levels at the top of the table with two tails, corresponding to 0 and 0.679. These alpha levels are 1 and 0.5. Therefore, the p-value of the test, which is 0.75, will be between 1 and 0.5. The p-value was confirmed using the TI-84 obtaining a similar p-value of 0.7994. Traditional Students (G1) Online Students (G2) mean 2.97 2.95 standard deviation 0.34 0.35 sample size 33 22 significance level: 0.05 degree of freedom: 53
- The chief financial officer is monitoring the raises for each department. The hypothesis is based on the premise that the management department has higher raises. Determine the critical value or values for a one-mean z-test at the 2% significance level if the hypothesis test is two-tailed (Ha:μ≠μ0). If there is only one critical value, leave the second answer box blank.In a single-factor ANOVA problem involving four populations or treatments with a random sample of five observations form each one, it is found that SSTr = 18.18 and SSE = 32. Use a significance level of 2.5%.a. State the null and alternative hypothesisb. Determine the critical value(s)c. Compute the test statistic valued. What is the conclusion for this test analysisA bank categorizes its customers into one of three groups based on their banking habits. A random sample of 30 customers from each group was selected, and the number of times each customer visited the bank during the past year was recorded. The following table shows the summary statistics. The bank manager will investigate whether there is a significant difference in mean numbers of bank visits for the groups. Multiple two-sample t-tests will be conducted, each at the significance level of α=0.05. The significance level (α) of a single hypothesis test is the probability of making a Type I error. The manager wants to know the probability of making a Type I error for multiple t-tests, not just for a single t-test. This probability is called the family error rate for Type I error, which is also known as the family error rate. A t-test has two possible outcomes: reject or do not reject the null hypothesis. Suppose the null hypothesis is true. If the null hypothesis is rejected, the…
- A repeated-measures analysis of variance for a study comparing four treatment conditions with a sample of n = 11 participants, produces an F-ratio of F = 3.71. For this result, which of the following is the correct statistical decision? Select one: a. Reject the null hypothesis with either a= .05 or a= .01. b. There is not enough information to determine the correct decision. c. Reject the null hypothesis with a= .05 but not with a= .01. d. Fail to reject the null hypothesis with either a= .05 or a= .01.A two-sample t-test for a difference in means was conducted to investigate whether the average time to swim a lap with the freestyle stroke is different from the average time to swim a lap with the butterfly stroke. With all conditions for inference met, the test produced a test statistic of t = -2.073 and a p-value of 0.042. Based on the p-value and a significance level of a = 0.05, which of the following is a correct conclusion? A There is convincing statistical evidence that the average time to swim a lap with the freestyle stroke is less than the average time to swim a lap with the butterfly stroke. в There is convincing statistical evidence that the average time to swim a lap with the freestyle stroke is different from the average time to swim a lap with the butterfly stroke. There is not convincing statistical evidence that the average time to swim a lap with the freestyle stroke is greater than the average time to swim a lap with the butterfly stroke. D There is not convincing…In a study to determine whether counseling could help people lose weight, a sample of people experienced a group-based behavioral intervention, which involved weekly meetings with a trained interventionist for a period of six months. The following data are the numbers of pounds lost for 14 people. Assume the population is approximately normal. Perform a hypothesis test to determine whether the mean weight loss is greater than 15 pounds. Use the α = 0.01 level of significance and the P-value method with the TI-84 Plus calculator. 22.9 28.8 8.1 24.4 21.7 13.4 17.6 21.5 37.8 34.1 12.6 36.8 24.6 19.9 Compute the P-value. Round the answer to at least four decimal places. P-value = ___ How do I solve this problem using TI-84 calculator?