An experiment can result in events A with probability, P(A) =0.6 and event B with probability, P(B) = 0.7. Assuming that P(A°nBC) = 0.1, compute the following probabilities: P(AUB) is: 0.30 0.70 0.20 0.90

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**Title: Probability Calculation of Events A and B**

**Introduction:**
In probability theory, understanding the relationship between different events is essential for computing their combined probabilities. Below is a problem that demonstrates how to compute the probability of the union of two events, given their individual probabilities and the probability of their intersection.

**Problem Statement:**
An experiment can result in events A with a probability of P(A) = 0.6 and event B with a probability of P(B) = 0.7. Assuming that P(A ∩ Bᶜ) = 0.1, compute the following probabilities:

**Question:**
P(A ∪ B) is:
   - 0.30
   - 0.70
   - 0.20
   - 0.90

**Explanation:**
To solve for P(A ∪ B), we need to understand the formula for the probability of the union of two events:
\[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \]

We are given:
\[ P(A) = 0.6 \]
\[ P(B) = 0.7 \]
\[ P(A ∩ Bᶜ) = 0.1 \]

First, we need to find \( P(A ∩ B) \). 
From the complement rule, we know that:
\[ P(A) = P(A ∩ B) + P(A ∩ Bᶜ) \]

Using this, we find \( P(A ∩ B) \):
\[ 0.6 = P(A ∩ B) + 0.1 \]
\[ P(A ∩ B) = 0.6 - 0.1 = 0.5 \]

Now, substituting the values into the union formula:
\[ P(A \cup B) = 0.6 + 0.7 - 0.5 = 1.3 - 0.5 = 0.8 \]

**Conclusion:**
Given the choices provided, the correct answer is not listed. However, the correct calculation for \( P(A \cup B) \) is 0.8. Therefore, none of the provided options (0.30, 0.70, 0.20, 0.90) correctly represent the probability of the union of events A and B based on the given data.

**Graphical
Transcribed Image Text:**Title: Probability Calculation of Events A and B** **Introduction:** In probability theory, understanding the relationship between different events is essential for computing their combined probabilities. Below is a problem that demonstrates how to compute the probability of the union of two events, given their individual probabilities and the probability of their intersection. **Problem Statement:** An experiment can result in events A with a probability of P(A) = 0.6 and event B with a probability of P(B) = 0.7. Assuming that P(A ∩ Bᶜ) = 0.1, compute the following probabilities: **Question:** P(A ∪ B) is: - 0.30 - 0.70 - 0.20 - 0.90 **Explanation:** To solve for P(A ∪ B), we need to understand the formula for the probability of the union of two events: \[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \] We are given: \[ P(A) = 0.6 \] \[ P(B) = 0.7 \] \[ P(A ∩ Bᶜ) = 0.1 \] First, we need to find \( P(A ∩ B) \). From the complement rule, we know that: \[ P(A) = P(A ∩ B) + P(A ∩ Bᶜ) \] Using this, we find \( P(A ∩ B) \): \[ 0.6 = P(A ∩ B) + 0.1 \] \[ P(A ∩ B) = 0.6 - 0.1 = 0.5 \] Now, substituting the values into the union formula: \[ P(A \cup B) = 0.6 + 0.7 - 0.5 = 1.3 - 0.5 = 0.8 \] **Conclusion:** Given the choices provided, the correct answer is not listed. However, the correct calculation for \( P(A \cup B) \) is 0.8. Therefore, none of the provided options (0.30, 0.70, 0.20, 0.90) correctly represent the probability of the union of events A and B based on the given data. **Graphical
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