Homework Help is Here – Start Your Trial Now!
Engineering
Chemical Engineering
An evaporator is used to concentrate 100kg/h of 10.0% salt solution. The evaporator operates such that 30% of the water entering the evaporator is evaporated, concentrating the outflow stream to 50.0% salt. Please answer each question shown below.

An evaporator is used to concentrate 100kg/h of 10.0% salt solution. The evaporator operates such that 30% of the water entering the evaporator is evaporated, concentrating the outflow stream to 50.0% salt. Please answer each question shown below.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
See similar textbooks
icon
Related questions
Question

An evaporator is used to concentrate 100kg/h of 10.0% salt solution. The evaporator operates such that 30% of the water entering the evaporator is evaporated, concentrating the outflow stream to 50.0% salt. Please answer each question shown below. 

This diagram represents a process flow through an evaporator system, with various streams of materials entering, mixing, and exiting. ### Description of Components and Streams: 1. **Stream 1 (Point 1):** - Mass flow rate (\( \dot{m}_1 \)): 100 kg/h - Water content (\( X_{W1} \)): 0.900 - Solid content (\( X_{S1} \)): 0.100 2. **Split Point (Sp1 at Point 2):** - Incoming stream is split into multiple streams. 3. **Stream 2 (Point 3):** - Mass flow rate (\( \dot{m}_2 \)): ? - Water content (\( X_{W2} \)): 0.900 - Solid content (\( X_{S2} \)): 0.100 4. **Stream 3 (Point 4):** - Mass flow rate (\( \dot{m}_3 \)): ? - Water content (\( X_{W3} \)): 0.900 - Solid content (\( X_{S3} \)): 0.100 5. **Mixer (Mx1 at Point 4):** - Combines incoming streams for processing in the evaporator. 6. **Stream 4 (Point 5):** - Mass flow rate (\( \dot{m}_4 \)): ? - Water content (\( X_{W4} \)): ? - Solid content (\( X_{S4} \)): ? 7. **Stream 5 (Steam at Point 5):** - Mass flow rate (\( \dot{m}_5 \)): ? - Water content (\( X_{W5} \)): 1.00 8. **Evaporator:** - Processes the mixed streams to adjust the moisture and solid content. 9. **Stream 6 (Point 6):** - Mass flow rate (\( \dot{m}_6 \)): ? - Water content (\( X_{W6} \)): 0.500 - Solid content (\( X_{S6} \)): 0.500 10. **Split Point (Sp2 at Point 6):** - Further splits the outgoing stream after evaporation. 11. **Stream 7 (Point
Transcribed Image Text:This diagram represents a process flow through an evaporator system, with various streams of materials entering, mixing, and exiting. ### Description of Components and Streams: 1. **Stream 1 (Point 1):** - Mass flow rate (\( \dot{m}_1 \)): 100 kg/h - Water content (\( X_{W1} \)): 0.900 - Solid content (\( X_{S1} \)): 0.100 2. **Split Point (Sp1 at Point 2):** - Incoming stream is split into multiple streams. 3. **Stream 2 (Point 3):** - Mass flow rate (\( \dot{m}_2 \)): ? - Water content (\( X_{W2} \)): 0.900 - Solid content (\( X_{S2} \)): 0.100 4. **Stream 3 (Point 4):** - Mass flow rate (\( \dot{m}_3 \)): ? - Water content (\( X_{W3} \)): 0.900 - Solid content (\( X_{S3} \)): 0.100 5. **Mixer (Mx1 at Point 4):** - Combines incoming streams for processing in the evaporator. 6. **Stream 4 (Point 5):** - Mass flow rate (\( \dot{m}_4 \)): ? - Water content (\( X_{W4} \)): ? - Solid content (\( X_{S4} \)): ? 7. **Stream 5 (Steam at Point 5):** - Mass flow rate (\( \dot{m}_5 \)): ? - Water content (\( X_{W5} \)): 1.00 8. **Evaporator:** - Processes the mixed streams to adjust the moisture and solid content. 9. **Stream 6 (Point 6):** - Mass flow rate (\( \dot{m}_6 \)): ? - Water content (\( X_{W6} \)): 0.500 - Solid content (\( X_{S6} \)): 0.500 10. **Split Point (Sp2 at Point 6):** - Further splits the outgoing stream after evaporation. 11. **Stream 7 (Point
Conduct a Degree of Freedom Analysis for each unit operation of the process. Calculate the flow rate of the product stream, which contains 40% salt. Calculate the recycle stream. Calculate the bypass stream. Calculate the steam leaving the process.
Transcribed Image Text:Conduct a Degree of Freedom Analysis for each unit operation of the process. Calculate the flow rate of the product stream, which contains 40% salt. Calculate the recycle stream. Calculate the bypass stream. Calculate the steam leaving the process.
Expert Solution
steps

Step by step

Solved in 5 steps with 1 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Similar questions
Recommended textbooks for you
Introduction to Chemical Engineering Thermodynami…
Introduction to Chemical Engineering Thermodynami…
Chemical Engineering
ISBN:
9781259696527
Author:
J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:
McGraw-Hill Education
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemical Engineering
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY
Elements of Chemical Reaction Engineering (5th Ed…
Elements of Chemical Reaction Engineering (5th Ed…
Chemical Engineering
ISBN:
9780133887518
Author:
H. Scott Fogler
Publisher:
Prentice Hall
Process Dynamics and Control, 4e
Process Dynamics and Control, 4e
Chemical Engineering
ISBN:
9781119285915
Author:
Seborg
Publisher:
WILEY
Industrial Plastics: Theory and Applications
Industrial Plastics: Theory and Applications
Chemical Engineering
ISBN:
9781285061238
Author:
Lokensgard, Erik
Publisher:
Delmar Cengage Learning
Unit Operations of Chemical Engineering
Unit Operations of Chemical Engineering
Chemical Engineering
ISBN:
9780072848236
Author:
Warren McCabe, Julian C. Smith, Peter Harriott
Publisher:
McGraw-Hill Companies, The
SEE MORE TEXTBOOKS