Saturated liquid ammonia is entering a 50 cm diameter 10-m long pipe at a steady 0.1 kg/s mass flow rateand a mean temperature of 0°C. It is exiting the pipe as saturated vapor at a mean temperature of 0°C.(a) What is the Reynolds number and flow regime at the beginning and at the end of the pipe?(b) If the surface temperature of the pipe can be assumed to be constant at 15°C in this section, whatis the average convection coefficient of the ammonia flow?(a) 1343; 27075(b) 553.6 W/m2K

Answered: Saturated liquid ammonia is entering a…

Introduction to Chemical Engineering Thermodynamics

8th Edition

ISBN:9781259696527

Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Chapter1: Introduction

Section: Chapter Questions

Problem 1.1P

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Question

Saturated liquid ammonia is entering a 50 cm diameter 10-m long pipe at a steady 0.1 kg/s mass flow rate
and a mean temperature of 0°C. It is exiting the pipe as saturated vapor at a mean temperature of 0°C.
(a) What is the Reynolds number and flow regime at the beginning and at the end of the pipe?
(b) If the surface temperature of the pipe can be assumed to be constant at 15°C in this section, what
is the average convection coefficient of the ammonia flow?
(a) 1343; 27075
(b) 553.6 W/m2K

Expert Solution

Step 1

Given:

Saturated liquid ammonia enters a pipe of diameter d = 0.5 m or 50 cm and L = 10 m.

The mass flow rate of ammonia is $\dot{m} = 0.1 kg / s$ and the mean temperature of T_in = T_out = 0^oC

(a) The Reynolds number at the beginning can be calculated as follows:

$Re = \frac{ρVd}{μ} Re = \frac{ρVd (\frac{π}{4} d)}{μ \times (\frac{π}{4} d)} (Multiplying and dividing by \frac{π}{4} d) Re = \frac{ρV (\frac{π}{4} d^{2})}{μ \times (\frac{π}{4} d)} Re = \frac{ρVA}{μ \times (\frac{π}{4} d)} (A is the area) Re = \frac{4 \dot{m}}{μπd} (1) (Since mass flow rate \dot{m} = ρVA)$