An equal tangent vertical curve is to be constructed between grades of +3.0% (initial) and -4.0% (final). The PVI is atstation 9+00 and at elevation 727 ft. Design acurve for a design speed of 60 mphon this crossing. Your design information must include the length of the curve, stations and elevations at PVC, PVT, and the high point of the curve.

Q: An old equal-tangent crest vertical curve was designed with a PVI at station 117+45 and elevation of…

A: An equal tangent crest vertical curve is as below The point PVC is called as the initial tangent…

Q: answer question 18 only

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Q: is having a radius of 120m and design speed as 80km find the total widening on the curve

A: According to given data  Mechanical Widening of the  Curve = 1.5 mCurve having a radius of =…

Q: Read the question carefully and give me right solution according to the question. Please I need…

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Q: 9. Assuming 0% grade, and AASHTO's recommended perception reaction time and recommer deceleration…

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Q: An SVC connects a -4% grade to a +4% grade. The curve goes under a pedestrian bridge at PVI. The…

A: Given:Vertical clearanceSight distanceHeight of drivers eyeHeight of objectTo find: Length of curve.

Q: > Transportation engineering textbook.pdf EXAMPLE 3.1 OLUTION Open w VERTICAL CURVE STATIONS AND…

A: I have tried to solve it in fresh with handwritten as per your demand plz go through it

Q: A downgrade of 2% intersects an upgrade of 4% at an elevation of 200 feet at station 55+15.00, where…

A: aMiddle ordinate =g2-g18L=0.04+0.028300=2.25m

Q: 19. What is the stationing (ft) of the EVC?

A: Length of curve, L = 1100ft  ⇒ 11 stations.   Stationing of BVC = 12+15 ft.

Q: A 500-m long equal tangent vertical curve has a point of vertical curvature at station 2 + 600 and…

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Q: A curve joins 0% grade with 12.5% grade. The point of intersection is at station 2+282.15 and…

A: PVCSTATION=PVISTA-L2PVCsta=2290.85-1582=2+211.85PVCELV=PVIELV-g1L2PVCelv=68.21+0×6502PVCelv=68.21

Q: have designed a vertical crest curve which joins a +3% E mph and you have determined the curve to be…

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Q: A rising grade of 1.5 percent meets a falling grade of 4.0 percent at station 2+400 of elevation…

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Q: Q3/ A vertical curve below has a lower point (A) which exists at station (53+50) with elevation…

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Q: Vertical summit curve has tangent grades of +1.5% and - 1.5% intersecting at station 4+000 at an…

A: Given- n1=+1.5%n2=-1.5%L=182

Q: 2300 ft equal tangent crest vertical curve is currently designed for 60 mph.this curve connects an…

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Q: An equal-tangent sag curve of length 920ft needs to be designed for 55 mph to connect an initial…

A: Given:- The length of the sag curve = 920 ft The design speed = 55 mph The initial downgrade = 5%…

Q: A vertical curve is used to connect the grades of +2% and -4%. Given that the length the vertical…

A: According to given data  vertical curve is used to connect the grades of +2% and -4% length the…

Q: highway engineer must stake a symmetrical vertical curve where an entering grade of +0.80% meets an…

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Q: A 1400-ft-long sag vertical curve (equal tangent) has a PVC at station 115 + 00 and elevation 750…

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Q: A 500-ft curve, grades of g₁-3.50% and 92-1.75%, VPI at station 38+00, and elevation 560.00 ft,…

A: A sag valley curve is given with Grade, g1 =-3.50% and g2 = -1.75%  VPI = 38+00  Elevation = 560 ft…

Q: Q-5 The mechanical widening of a curve is 1.5m, the curve is having a radius of 120m and design…

A: given- mechanical widening=1.5 mradius of curve=120 mdesign speed=80 kmph

Q: A vertical curve's PVI has a station of 25+00 and an elevation of 192.36'. The incoming grade is…

A: Draw FBD:

Q: A 400-ft equal-tangent sag vertical curve has its PVC at station 78+00 and elevation 800 ft. The…

A: Length of curve (L) = 400 ftStation of PVC = 78+00Elevation of PVC = 800 ft

Q: You have designed a vertical crest curve which joins a +3% grade and a -4% grade. The design speed…

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Q: An equal-tangent vertical curve is to be constructed between grades of +1%(initial) and -1%(final).…

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Q: D] Calculate the centerline elevations for PVC, VPI, PVT, station 32+00, and turning point (highest…

A: Consider the free body diagram,;

Q: Estimate the support reactions in the beam shown below. The flexural rigidity, EI of the beam is…

A: fixed end moment: MAB¯=-8×3212=-6 KN-mMBA¯=+8×3212=6 KN-mMBC¯=-8×2212-20×28=-7.666…

Q: you have determined the curve to be 1100 ft long. Now, you need to when the BVC is located at…

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Q: An equal-tangent vertical curve connects an initial grade of -4% and a final grade of +1% and is…

A: The objective of the problem is to determine the station and elevation of the lowest point on an…

Q: A +1.512% grade meets a -1.785% grade at PVI Station 31+50, elevation 562.00. The Equal Tangent…

A: Given:- The initial grade of the curve = +1.512% The final grade of the curve = -1.785% The station…

Q: A-3% grade us connected to a +1.0% grade by means of 180m vertical curve. The point of intersection…

A: Length of curve= 180m Grades: g1 =-3%, g2=1%

Q: A +2% grade intersects with a -1% grade at station (535-24.25) at an elevation of 300 ft. If the…

A: Solution:-Given,Elevation=300ftDesign speed=60 mi/hg1=2%g2=-1%

Q: 3.16 A 1400-ft-long sag vertical curve (equal tangent) has a PVC at station 115 + 00 and elevation…

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Q: An equal tangent vertical curve connects a 1% and 3% initial and final grade. Design speed is…

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Q: What are the reasons for preferring to use a three-centered compound curve at intersections?

A: Brief Concept- Three-Centered Compound Curve- It is a curve that is made up of two or more circular…

Q: Step by step solutionProblem 1. An existing equal-tangent sag vertical curve is designed for 60 mph.…

A: Step 1:Step 2: Step 3: Step 4:

Q: C-A -3% grade is connected to a +4% grade for a vertical curve. The PC. station is 00 and PC.…

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Q: A-1.7% grade intersects a 3.6% grade on a highway with a design speed of 55 mph. What is the length…

A: Design speed= 55 mph

Q: A sag vertical curve joins a -6% grade and +5% grades. s at Station 355+50 and at an elevation of…

A: Calculating the SSD: SSD=1.47vt+v23011.232.2-GSSD=1.4760×2.5+6023011.232.2-0.06SSD=637.42 ft

Q: Q3: What is the minimum radius of horizontal curve for a design speed of 90 kph ?

A: Solution  Given Data V=90 kph

Q: A 16% grade meets a 7% grade at station 2 + 265 of elevation 250 m. The lengths are L1 = 115 m. and…

A: The grades are, g1=16%g2=7% The lengths are, L1=115 mL2=90 m The elevation is 250 m.

Q: What is the minimum radius of horizontal curve for a design speed of 90 kph ?

A: The given data is: Design Speed (V) = 90 kmph

Q: You have designed a vertical crest curve which joins a +3% grade and a -4% grade. The design speed…

A: The given data is shown below: Grades=+3% and -4% gradeDesign speed=60 mi/hLength of…