An equal tangent vertical curve is to be constructed between grades of -2.0% (initial) and 1.0% (final). The PVIis at station 11 + 000.000 and at elevation 420 m. Due to a street crossing the roadway, the elevation of theroadway at station 11 + 071.000 must be at 421.5 m. Design the curve.Use the editor to format your answer

Consider the given data G1=-2%G2=+1%PVI station = 11+000.000PVI Elevation=420…

Answered: An equal tangent vertical curve is to…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Similar questions

A crest vertical curve joining a + 3 percent and – 4 percent grade is to be designed for 75 mph. If the tangent intersect at station (345 + 6000) at an elevation of 250 ft, determine the stations and elevations of the PVC and PVT.
An equal-tangent curve connects a +1.0% and a -0.5% grade. The PVC is at station 54+24 and the PVI is at station 56+92. Is this curve long enough to provide passing sight distance for a 60-mi/r design speed? Problem 2
A grade of -3.0% is followed by a grade of +2.1% which intersects at station 10+250 and elevation of 110 m. If the maximum change in grade per 20 m station is 0.20%, determine the following A. Length of parabolic curve that shall connect these two gradelines. B. Elevation of PC. C. Elevation of a point on the curve @ Sta.10+250.
I need the answer as soon as possible
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A +4.0% grade intersects a -3.0% percent grade at PVI Sta. 222+00 and Elevation 300.00 on a two-lane highway with a design speed of 45 mph. Assume AASHTO Standards. 1. Determine the minimum length for the curve that is designed to meet passing sight distance using K-value method 2. Determine the Station and Elevation of the PVC
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Consider the same vertical curve from Problem 1 that has a +3.2% initial grade and -1.1% final grade. The point of vertical intersection is at station 98+20. The highest point of the curve is at station 100+79.35 to meet drainage design. What is the station of the point of vertical curvature (Also known as beginning of vertical curve). 92+88.95 92+90.81 92+88.05 (INCORRECT) 92+91.23 This is Question 1: Consider a vertical curve with a +3/2% initial grade and -1.1% final grade. The point of vertical intersection is at station 98+20. The highest point of the curve is at station 100+79.35 to meet drainage design. What is the design speed, in mph? Correct answer here is 70 MPH

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An equal tangent vertical curve is to be constructed between grades of -2.0% (initial) and 1.0% (final). The PVI is at station 11 + 000.000 and at elevation 420 m. Due to a street crossing the roadway, the elevation of the roadway at station 11 + 071.000 must be at 421.5 m. Design the curve.