An engineer working in an electronics lab connects a parallel-plate capacitor to a battery, so that the potential difference between the plates is 230 V. Assume a plate separation of d = 1.38 cm and a plate area of A - 25.0 cm. When the battery is removed, thecapacitor is plunged into a container of distilled water. Assume distilled water is an insulator with a dielectric constant of 80.0.d into(a) Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.)O - 369Q, = 369beforeV pcafterv pC(b) Determine the capacitance (in F) and potential difference (in V) after immersion.C, - 128You will naed to include a dielectric constant when you calculate the final capacitance. Nota that x= 80 for distillad water. FAV, =(c) Determine the change in energy (in n)) of the capacitor.Au:(d) what If? Repeat parts (a) through (c) of the problem in the case that the capacitor is immersed in distilled water while still connected to the 230 V potential difference.Calculate the charge on the plates (in pc) before and after the capacitor is submerged. (Enter the magnitudes.)beforepcafterQ: =pCDetermine the capacitance (in F) and potential difference (in V) after inmmersion.AV, =Determine the change in energy (In n) of the capacitor.AU =Need Help?Read it

Given, For a parallel plate capacitor The potential difference between the plates is V = 230V the…

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