A parallel plate capacitor with a capacitance of 0.86 F with a has plate area A and are separated by a distance d. It is charged up to 11 V. The capacitor is now disconnected from the battery. If the area of the plates increases by a factor of 3 and the separation decreases by a factor of 10, fınd the new charge on the capacitor in Coulombs.
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Given:
The capacitance of the capacitor is C=0.86 F.
The voltage is V=11 V.
The area o the plate is A.
The distance between the plate is d.
The expression for capacitance is:
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