An engineer wants to know if producing metal bars using a new experimental treatment rather than the conventional treatment makes a difference in the tensile strength of the bars (the ability to resist tearing when pulled lengthwise). Atα=0.02,answer parts (a) through (e). Assume the population variances are equal and the samples are random. If convenient, use technology to solve the problem. TreatmentTensile strengths (newtons per square millimeter)Experimental400413434409420377392 Conventional381446436350404354375361355386 (a) Identify the claim and stateH0andHa. The claim is "The new treatment▼ makes a differencedoes not make a differencein the tensile strength of the bars."What areH0andHa? The null hypothesis,H0,is▼ mu 1 equals mu 2μ1=μ2mu 1 less than or equals mu 2μ1≤μ2mu 1 greater than or equals mu 2μ1≥μ2.The alternative hypothesis,Ha,is▼ mu 1 not equals mu 2μ1≠μ2mu 1 greater than mu 2μ1>μ2mu 1 less than mu 2μ1<μ2.Which hypothesis is the claim? The alternative hypothesis, Ha The null hypothesis, H0(b) Find the critical value(s) and identify the rejection region(s). Enter the critical value(s) below. nothing(Type an integer or decimal rounded to three decimal places as needed. Use a comma to separate answers as needed.)Select the correct rejection region(s) below. A.t<−t0, t>t0 B.t<−t0 C.t>t0 D.−t0<t<t0(c) Find the standardized test statistic. t=nothing(Type an integer or decimal rounded to the nearest thousandth as needed.)(d) Decide whether to reject or fail to reject the null hypothesis. ▼ Fail to rejectRejectthe null hypothesis.(e) Interpret the decision in the context of the original claim. At the2%significance level,▼ there is notthere isenough evidence to support the claim.

(a) Identify the claim and state H0 and Ha. The claim is "The new treatment makes a difference…

Answered: An engineer wants to know if producing…

MATLAB: An Introduction with Applications

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Author:Amos Gilat

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An engineer wants to know if producing metal bars using a new experimental treatment rather than the conventional treatment makes a difference in the tensile strength of the bars (the ability to resist tearing when pulled lengthwise). At

α=0.02,

answer parts (a) through (e). Assume the population variances are equal and the samples are random. If convenient, use technology to solve the problem.

Treatment

Tensile strengths (newtons per square millimeter)

Experimental

400

413

434

409

420

377

392

Conventional

381

446

436

350

404

354

375

361

355

386

(a) Identify the claim and state

and

Ha.

The claim is "The new treatment

▼

makes a difference

does not make a difference

in the tensile strength of the bars."

What are

and

Ha?

The null hypothesis,

H0,

▼

mu 1 equals mu 2μ1=μ2

mu 1 less than or equals mu 2μ1≤μ2

mu 1 greater than or equals mu 2μ1≥μ2

The alternative hypothesis,

Ha,

▼

mu 1 not equals mu 2μ1≠μ2

mu 1 greater than mu 2μ1>μ2

mu 1 less than mu 2μ1<μ2

Which hypothesis is the claim?

The alternative hypothesis, Ha

The null hypothesis, H0

(b) Find the critical value(s) and identify the rejection region(s).

Enter the critical value(s) below.

nothing

(Type an integer or decimal rounded to three decimal places as needed. Use a comma to separate answers as needed.)

Select the correct rejection region(s) below.

t<−t0, t>t0

t<−t0

t>t0

−t0<t<t0

t=nothing

(Type an integer or decimal rounded to the nearest thousandth as needed.)

(d) Decide whether to reject or fail to reject the null hypothesis.

▼

Fail to reject

Reject

the null hypothesis.

(e) Interpret the decision in the context of the original claim.

At the

significance level,

▼

there is not

there is

enough evidence to support the claim.

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