An engineer is measuring a quantity 0. It is assumed that there is a random error in each measurement, so the engineer will take n measurements and report the average of the measurements as the estimated value of 0. Here, n is assumed to be large enough so that the central limit theorem applies. If X, is the value that is obtained in the ith measurement, we assume that X; = 0 + W, where W, is the error in the ith measurement. We assume that the W,'s are i.i.d. with EW, = 0 and Var(") = 4 units. The engineer reports the average of the measurements X, + X2+...+X, X = How many measurements does the engineer need to make until he is 90% sure that the final error is less than 0.25 units? In other words, what should the value of n be such that P(0 – 0.25 < X <0 + 0.25) 2 .90?
An engineer is measuring a quantity 0. It is assumed that there is a random error in each measurement, so the engineer will take n measurements and report the average of the measurements as the estimated value of 0. Here, n is assumed to be large enough so that the central limit theorem applies. If X, is the value that is obtained in the ith measurement, we assume that X; = 0 + W, where W, is the error in the ith measurement. We assume that the W,'s are i.i.d. with EW, = 0 and Var(") = 4 units. The engineer reports the average of the measurements X, + X2+...+X, X = How many measurements does the engineer need to make until he is 90% sure that the final error is less than 0.25 units? In other words, what should the value of n be such that P(0 – 0.25 < X <0 + 0.25) 2 .90?
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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Question
![An engineer is measuring a quantity 0. It is assumed that there is a random error in
each measurement, so the engineer will take n measurements and report the average
of the measurements as the estimated value of 0. Here, n is assumed to be large
enough so that the central limit theorem applies. If X, is the value that is obtained in
the ith measurement, we assume that
X; = 0 + W,,
where W, is the error in the ith measurement. We assume that the W,'s are i.i.d. with
EW, = 0 and Var(") = 4 units. The engineer reports the average of the
measurements
X, + X2+..+X,
X =
How many measurements does the engineer need to make until he is 90% sure that
the final error is less than 0.25 units? In other words, what should the value of n be
such that
P(0 – 0.25 < X < 0 + 0.25) > .90?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbbef09ef-c01e-4be4-995e-73ac2238c8cb%2F69fc1dbc-54b5-43ea-afc4-cc72f409ec94%2F39g8l0r_processed.jpeg&w=3840&q=75)
Transcribed Image Text:An engineer is measuring a quantity 0. It is assumed that there is a random error in
each measurement, so the engineer will take n measurements and report the average
of the measurements as the estimated value of 0. Here, n is assumed to be large
enough so that the central limit theorem applies. If X, is the value that is obtained in
the ith measurement, we assume that
X; = 0 + W,,
where W, is the error in the ith measurement. We assume that the W,'s are i.i.d. with
EW, = 0 and Var(") = 4 units. The engineer reports the average of the
measurements
X, + X2+..+X,
X =
How many measurements does the engineer need to make until he is 90% sure that
the final error is less than 0.25 units? In other words, what should the value of n be
such that
P(0 – 0.25 < X < 0 + 0.25) > .90?
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can you explain ? thank you !
![By our discussion above, the 95% Confidence
interval for 0 = Ex; is given by
6
(x - 2 € √ X + 25 ²5 ).
-
ท](https://content.bartleby.com/qna-images/question/47f6c1da-c6df-426c-81ec-6020162a0815/33fd0777-de23-4742-a454-2da5a3a7bec9/kdz7p3p_thumbnail.png)
Transcribed Image Text:By our discussion above, the 95% Confidence
interval for 0 = Ex; is given by
6
(x - 2 € √ X + 25 ²5 ).
-
ท
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