A vehicle with a particular defect in its emission control system is taken to a succession of randomly selected mechanics until r = 16 of them have correctly diagnosed the problem. Suppose that this requires diagnoses by 20 different mechanics (so there were 4 incorrect diagnoses). Let p = P(correct diagnosis), so p is the proportion of all mechanics who would correctly diagnose the problem. What is the mle of p?p̂ = Is it the same as the mle if a random sample of 20 mechanics results in 16 correct diagnoses? Explain.No, the formula for the first one is (number of failures)/(number of trials) and the formula for the second one is (number of successes)/(number of failures).No, the formula for the first one is (number of failures)/(number of trials) and the formula for the second one is (number of successes)/(number of trials). Yes, both mles are equal to the fraction (number of successes)/(number of failures).No, the formula for the first one is (number of successes)/(number of failures) and the formula for the second one is (number of failures)/(number of trials).Yes, both mles are equal to the fraction (number of successes)/(number of trials).How does the mle compare to the estimate resulting from the use of the unbiased estimator p̂ = r − 1r + x − 1?The mle is greater than the the unbiased estimator.The mle is less than the the unbiased estimator. The mle is equal to the the unbiased estimator. A vehicle with a particular defect in its emission control system is taken to a succession of randomly selected mechanics until r = 16 of them have correctly diagnosed the problem. Suppose that this requiresdiagnoses by 20 different mechanics (so there were 4 incorrect diagnoses). Let p = P(correct diagnosis), so p is the proportion of all mechanics who would correctly diagnose the problem. What is the mle of p?p =Is it the same as the mle if a random sample of 20 mechanics results in 16 correct diagnoses? Explain.O No, the formula for the first one is (number of failures)/(number of trials) and the formula for the second one is (number of successes)/(number of failures).No, the formula for the first one is (number of failures)/(number of trials) and the formula for the second one is (number of successes)/(number of trials).Yes, both mles are equal to the fraction (number of successes)/(number of failures).O No, the formula for the first one is (number of successes)/(number of failures) and the formula for the second one is (number of failures)/(number of trials).O Yes, both mles are equal to the fraction (number of successes)/(number of trials).How does the mle compare to the estimate resulting from the use of the unbiased estimator p=O The mle is greater than the the unbiased estimator.O The mle is less than the the unbiased estimator.O The mle is equal to the the unbiased estimator.r - 1r+ x - 1

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Answered: cle with a particular defect in its…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

A vehicle with a particular defect in its emission control system is taken to a succession of randomly selected mechanics until

r = 16 of them have correctly diagnosed the problem. Suppose that this requires diagnoses by 20 different mechanics (so there were 4 incorrect diagnoses). Let p = P(correct diagnosis), so p is the proportion of all mechanics who would correctly diagnose the problem. What is the mle of p?

p̂ =

Is it the same as the mle if a random sample of 20 mechanics results in 16 correct diagnoses? Explain.

No, the formula for the first one is (number of failures)/(number of trials) and the formula for the second one is (number of successes)/(number of failures).

No, the formula for the first one is (number of failures)/(number of trials) and the formula for the second one is (number of successes)/(number of trials).

Yes, both mles are equal to the fraction (number of successes)/(number of failures).

No, the formula for the first one is (number of successes)/(number of failures) and the formula for the second one is (number of failures)/(number of trials).

Yes, both mles are equal to the fraction (number of successes)/(number of trials).

How does the mle compare to the estimate resulting from the use of the unbiased estimator

p̂ =

r − 1

r + x − 1

The mle is greater than the the unbiased estimator.

The mle is less than the the unbiased estimator.

The mle is equal to the the unbiased estimator.