**Problem:**An engineer fashions a 3.9-kΩ equivalent resistor from a parallel combination of 4 equal-value resistors. What is the resistance (in kΩ) of each individual resistor?**Solution Explanation:**When resistors are combined in parallel, the reciprocal of the total or equivalent resistance (\(R_{eq}\)) is the sum of the reciprocals of each individual resistance (\(R\)).For \(n\) equal resistors in parallel, the equation is:\[\frac{1}{R_{eq}} = \frac{n}{R}\]Given:- \(R_{eq} = 3.9 \, \text{kΩ}\)- \(n = 4\)We need to find the resistance \(R\) of each resistor.From the formula, we have:\[\frac{1}{3.9} = \frac{4}{R}\]Solving for \(R\):\[R = \frac{4}{\frac{1}{3.9}}\]\[R = 4 \times 3.9\]\[R = 15.6 \, \text{kΩ}\]Therefore, the resistance of each individual resistor is 15.6 kΩ.

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An engineer fashions an 3.9-k equivalent resistor from a parallel combination of 4 equal- value resistors. What is the resistance (in k) of each individual resistor?