An engine with an output of 249.0 W has an efficiency of 25.0 %. It works at 10.00 cycles/s. How much work is done in each cycle?
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Q: An engine with an output of 249.0 W has an efficiency of 25.0 %. It works at 10.00 cycles/s. How…
A: It is given that the output power is 249.0W. It is the work done per second. This implies, 249.0 J…
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A: Heat supplied per hour P=WtP=ηQtQt=Pη
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Q: from a hot reservoir at
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A: Given data: Work done W=1500J Heat exhausted QC=3200J
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