Answered: An engine absorbs 1.71 kJ from a hot…

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter18: Heat Engines, Entropy, And The Second Law Of Thermodynamics

Section: Chapter Questions

Problem 1P

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Question

An engine absorbs 1.71 kJ from a hot reservoir at 277°C and expels 1.22 kJ to a cold reservoir at 27°C in each cycle.

(a) What is the engine's efficiency?
%

(b) How much work is done by the engine in each cycle?
J

(c) What is the power output of the engine if each cycle lasts 0.301 s?
kW

Expert Solution

Step 1

Given data:

The heat absorbed by the engine is $Q_{a} = 1.71 kJ$
The temperature of the hot reservoir is $T_{h} = 277 ° C = 550 K$
The heat expelled is $Q_{e} = 1.22 kJ$
The temperature of the cold reservoir is $T_{c} = 27 ° C = 300 K$

Part a:

Calculating the efficiency of the engine as follows:

$\begin{array}{rcl} η & = & (\frac{Q_{a} - Q_{e}}{Q_{a}}) \times 100 \\ = & (\frac{1.71 - 1.22}{1.71}) \times 100 \\ = & 28.65 % \end{array}$

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