An elevator cab and its load have a combined mass of 1600 kg. With a supporting cable, the cab is originally moving downward at 12 m/s, but then brought to rest with constant acceleration in a distance of 42 m. What are the directions of the following forces acting on the elevator cab-load system? Choose from the following directions: (north, south) Tension in the supporting cable: Blank 1 gravitational force: Blank 2 Calculate the magnitude of the gravitational force acting on the elevator cab-load system. Use g = 9.8 m/s^2. Fg - Blank 3 N Calculate the magnitude of the constant acceleration of the system. a = Blank 4 m/s^2 What is the direction of this acceleration? (north or south)? answer: Blank 5 Since the direction of acceleration is opposite that of the direction of the initial velocity, the system is "slowing down" or "speeding up"? answer: Blank 6 Solve for F = Blank 7 N What is the magnitude of the tension force along the supporting cable? tension - Blank 8 N

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Chapter1: Units, Trigonometry. And Vectors
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An elevator cab and its load have a combined mass of 1600 kg. With a supporting cable, the cab is originally moving downward at 12
m/s, but then brought to rest with constant acceleration in a distance of 42 m.
What are the directions of the following forces acting on the elevator cab-load system?
Choose from the following directions: (north, south)
Tension in the supporting cable: Blank 1
gravitational force: Blank 2
Calculate the magnitude of the gravitational force acting on the elevator cab-load system. Use g = 9.8 m/s^2.
Fg - Blank 3 N
Calculate the magnitude of the constant acceleration of the system.
a = Blank 4 m/s^2
What is the direction of this acceleration? (north or south)?
answer: Blank 5
Since the direction of acceleration is opposite that of the direction of the initial velocity, the system is "slowing down" or "speeding
up"?
answer: Blank 6
solve for Σ r = Blank 7 N
What is the magnitude of the tension force along the supporting cable?
tension = Blank 8 N
Transcribed Image Text:An elevator cab and its load have a combined mass of 1600 kg. With a supporting cable, the cab is originally moving downward at 12 m/s, but then brought to rest with constant acceleration in a distance of 42 m. What are the directions of the following forces acting on the elevator cab-load system? Choose from the following directions: (north, south) Tension in the supporting cable: Blank 1 gravitational force: Blank 2 Calculate the magnitude of the gravitational force acting on the elevator cab-load system. Use g = 9.8 m/s^2. Fg - Blank 3 N Calculate the magnitude of the constant acceleration of the system. a = Blank 4 m/s^2 What is the direction of this acceleration? (north or south)? answer: Blank 5 Since the direction of acceleration is opposite that of the direction of the initial velocity, the system is "slowing down" or "speeding up"? answer: Blank 6 solve for Σ r = Blank 7 N What is the magnitude of the tension force along the supporting cable? tension = Blank 8 N
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