### Problem DescriptionTwo blocks are connected by a massless rope over a massless, frictionless pulley, as depicted in the figure. The setup includes:- **Block 2**: Mass (\(m_2\)) is 10.1 kg.- **Coefficient of Kinetic Friction** (\(\mu_k\)) between block 2 and the incline is 0.200.- **Incline Angle** (\(\theta\)) is 27.5°.The problem asks: If block 2 is moving up the incline at a constant speed, what is the mass (\(m_1\)) of block 1?### Diagram Explanation- The diagram shows a pulley system with: - **Block 1** (red, labeled as "1") vertically hanging on one side of the pulley. - **Block 2** (blue, labeled as "2") positioned on a green incline.- The incline has an angle (\(\theta\)) indicated at its base, showing the orientation of block 2 on the slope. ### Solution Attempt- The provided incorrect calculation for \(m_1\) is \(-2.8744\) kg.### Important Notes- **Constant Speed** implies zero net acceleration. Therefore, the forces on both sides of the pulley system need to be balanced.- **Kinetic Friction** opposes the motion of block 2 up the incline.

Answered: Image /qna-images/answer/2536f616-0b9d-425e-bbf4-d3cac292b06e.jpg

Answered: Hk = 0.200. The angle 0 of the incline…

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Hk = 0.200. The angle 0 of the incline is 27.5°. If block 2 is moving up the incline at constant speed, what is the mass m of block 1?