**Statistical Hypothesis Testing for Manufacturing Process Efficiency**An electronics manufacturing process has historically had a mean completion time of 65 minutes. It is claimed that, due to improvements in the process, the mean completion time, $ \mu $, is now less than 65 minutes. A random sample of 22 completion times using the new process is taken. The sample has a mean completion time of 59 minutes, with a standard deviation of 12 minutes.Assume that completion times using the new process are approximately normally distributed. At the 0.05 level of significance, can it be concluded that the population mean completion time using the new process is less than 65 minutes?Perform a one-tailed test. Then complete the parts below.Carry your intermediate computations to three or more decimal places. (If necessary, consult a [list of formulas](#).)---**Tasks:**(a) **State the null hypothesis $ H_0 $ and the alternative hypothesis $ H_1 $:**- $ H_0: $ [Blank]- $ H_1: $ [Blank](b) **Determine the type of test statistic to use:** - (Choose from options such as Z-test, t-test, etc.)(c) **Find the value of the test statistic:** - (Round to three or more decimal places.)- [Blank](d) **Find the critical value:** - (Round to three or more decimal places.)- [Blank](e) **Can it be concluded that the mean completion time using the new process is less than 65 minutes?**- [ ] Yes- [ ] No---**Graphical Interface:**The image includes a calculator-like interface with statistical symbols such as $ \mu, \sigma, \rho $, and operations. This interface is presumably used for selecting statistical symbols and operations to aid in hypothesis formulation and calculations.

Hello! As you have posted more than 3 sub parts, we are answering the first 3 sub-parts. In case you require the unanswered parts also, kindly re-post that parts separately. Given claim: The population mean completion time using the new process is less than 65 minutes. a) Null Hypothesis: H0:μ≥65 Alternative Hypothesis: H1:μ<65b) In the given situation, The sample size (=22) is less than 30 and the population standard deviation is not known. From the alternative, the test is left tailed test. Hence, the suitable test is t test with left tailed. c) Test statistic: t=x¯-μsn=59-651222=-2.3452