An electron with a kinetic energy of 44.34 eV is incident on a square barrier with Ub = 57.43 eV and w = 2.200 nm. What is the probability that the electron tunnels through the barrier? (Use 6.626 x 103ª J × S for h, 9.109 x 1031 kg for the mass of an electron, and 1.60 × 1019 C for the charge of an electron.)
An electron with a kinetic energy of 44.34 eV is incident on a square barrier with Ub = 57.43 eV and w = 2.200 nm. What is the probability that the electron tunnels through the barrier? (Use 6.626 x 103ª J × S for h, 9.109 x 1031 kg for the mass of an electron, and 1.60 × 1019 C for the charge of an electron.)
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The first screenshot displays the question, and the second screenshot displays the section of the book that's relevant to the problem. So far, there have been two incorrect answers given:
a.) 2.82 x e^-(1.51 x 10^12), and
b.) (1.60*10^-19)^-(2.04*10^11)
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Transcribed Image Text:An electron with a kinetic energy of 44.34 eV is incident on a square barrier with Ub = 57.43 eV and w =
2.200 nm. What is the probability that the electron tunnels through the barrier? (Use 6.626 x 1034 J x S
for h, 9.109 x 101 kg for the mass of an electron, and 1.60 x 10 19 C for the charge of an electron.)
-31
Transcribed Image Text:This effect is known as barrier tunneling or quantum tunneling. The probability of tunneling
through a rectangular barrier is given by:
Prunnel = eY
where
327²mw² (U, – K;)
h2
-
and w is the width of the barrier.
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