An electron moves at speed 5.6×10 m/s toward the velocity selector shown in (Figure 1), where the electric field is hidden from view. A 0.12-T magnetic field points into the paper. A) Determine the magnitude of the magnetic force that the magnetic field exerts on the electron. F=? B) What E→ field magnitude is required so that the electric force exerted on the electron is equal in magnitude and opposite in direction to the magnetic force? E =?
An electron moves at speed 5.6×10 m/s toward the velocity selector shown in (Figure 1), where the electric field is hidden from view. A 0.12-T magnetic field points into the paper.
A) Determine the magnitude of the magnetic force that the magnetic field exerts on the electron.
F=?
B) What E→ field magnitude is required so that the electric force exerted on the electron is equal in magnitude and opposite in direction to the magnetic force?
E =?
Given:
The speed of the electron is given as:
The magnetic field is given as:
The charge of the electron is:
To find:
The magnetic force on the electron:
The electric field required to produce a force with the same magnitude as the magnetic force and opposite direction:
According to Lorentz Force law, the force on a charged particle moving in a magnetic field is given by the formula:
where,
is the magnetic force on the charged particle,
is the charge on the particle,
is the velocity of the charged particle and
is the magnetic field.
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