Hello, i need assitance in solving the following question. An electron microscope focuses electrons through magnetic lenses to observe objects at highermagnification than is possible with a light microscope. For any microscope, the smallest object that canbe observed is one-half the wavelength of the radiation used. Thus, for example, the smallest object thatcan be observed with light of 400.0 nm is 2.00 × 10-7 m.(a) What is the smallest object observable with an electron microscope using electrons moving at5.80 × 104 m/s?X 10 (select) m (Enter your answer in scientific notation.)(b) At 2.60 × 107 m/s?X 10 (select)m (Enter your answer in scientific notation.)

Given , For any microscope the smallest object that can be observed is half of the wavelength of the radiation .(a) Velocity , v=5.80×104ms Using De- Broglie equation : λ=hmvwhere,h= Planck's Constant = 6.634×10-34 J sm= mass of electron =9.11×10-31 Kgv=velocity = 5.80×104 msPutting values :λ=6.634×10-34 m2k\g s9.11×10-31 kg×5.80×104msλ=1.255×10-8 m So, smallest object observable : =λ2=1.255×10-8 m2=6.275×10-9 m(b)Here, velocity 2.60×107 ms Using De- Broglie equation : λ=hmvwhere,h= Planck's Constant = 6.634×10-34 J sm= mass of electron =9.11×10-31 Kgv=velocity = 2.60×107 msPutting values :λ=6.634×10-34 m2k\g s9.11×10-31 kg×2.60×107msλ=2.80×10-11 m So, smallest object observable : =λ2=2.80×10-11 m2=1.4×10-11 m