Gg ▼Part AAn electron is to be accelerated from a velocity of 1.50x106 m/s to a velocity of 9.00x106 m/s. Through what potential difference must the electron pass to accomplish this?Vinitial - Vfinal = -224 VSubmit✓ CorrectSet Up: Apply conservation of energy, Eq. (18.3). Use Eq. (18.10) to express U in terms of V.Solve: K₁+qV₁ = K₂ +qV₂Previous Answersq(V₁ V₂) = K2 - K₁iq=-1.602 × 10-¹⁹ CK₁ = mv² = 3.69 × 10-¹7J; K₂ = 1/mev² = 1.02 × 10-¹8 JV₁ V₂ =K₂-K₁9Reflect: The electron gains kinetic energy when it moves to higher potential.Part B-= -224VThrough what potential difference must the electron pass if it is to be slowed from 9.00x106 m/s to a halt?Vinitial - Vfinal =1971 ΑΣΦ- 172.76Submit Previous Answers Request AnswerX Incorrect; Try Again; 8 attempts remaining?V

For Part(a):Initial velocity of electron is Final velocity of electron is Note:Charge on electron is…

Answered: An electron is to be accelerated from a…

An electron is to be accelerated from a velocity of 1.50x105 m/s to a velocity of 9.00x105 m/s. Through what potential difference must the electron pass to accomplish this?

College Physics

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ISBN:9781305952300

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Chapter1: Units, Trigonometry. And Vectors

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Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

▼
Part A
An electron is to be accelerated from a velocity of 1.50x106 m/s to a velocity of 9.00x106 m/s. Through what potential difference must the electron pass to accomplish this?
Vinitial - Vfinal = -224 V
Submit
✓ Correct
Set Up: Apply conservation of energy, Eq. (18.3). Use Eq. (18.10) to express U in terms of V.
Solve: K₁+qV₁ = K₂ +qV₂
Previous Answers
q(V₁ V₂) = K2 - K₁iq=-1.602 × 10-¹⁹ C
K₁ = mv² = 3.69 × 10-¹7J; K₂ = 1/mev² = 1.02 × 10-¹8 J
V₁ V₂ =
K₂-K₁
9
Reflect: The electron gains kinetic energy when it moves to higher potential.
Part B
-
= -224V
Through what potential difference must the electron pass if it is to be slowed from 9.00x106 m/s to a halt?
Vinitial - Vfinal =
1971 ΑΣΦ
- 172.76
Submit Previous Answers Request Answer
X Incorrect; Try Again; 8 attempts remaining
?
V

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Step 4: Calculation for potential difference for part(a).

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