An electron is released from rest at the negative plate of a parallel plate capacitor and accelerates to the positive plate (see the drawing). The plates are separated by a distance of 1.1 cm, and the electric field within the capacitor has a magnitude of 2.7 x 10° V/m. What is the kinetic energy of the electron just as it reaches the positive plate?
An electron is released from rest at the negative plate of a parallel plate capacitor and accelerates to the positive plate (see the drawing). The plates are separated by a distance of 1.1 cm, and the electric field within the capacitor has a magnitude of 2.7 x 10° V/m. What is the kinetic energy of the electron just as it reaches the positive plate?
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![An electron is released from rest at the negative plate of a parallel plate capacitor and accelerates to the positive plate (see the
drawing). The plates are separated by a distance of 1.1 cm, and the electric field within the capacitor has a magnitude of 2.7 x 10 V/m.
What is the kinetic energy of the electron just as it reaches the positive plate?
Electric field
Electron
KEpositive =
+ ++++ ...++](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fae21ec2e-58d8-4f15-bf44-31808a63ebda%2F35e19f60-20dd-4b4f-a427-b6e6c24601df%2Fvvfxb28_processed.jpeg&w=3840&q=75)
Transcribed Image Text:An electron is released from rest at the negative plate of a parallel plate capacitor and accelerates to the positive plate (see the
drawing). The plates are separated by a distance of 1.1 cm, and the electric field within the capacitor has a magnitude of 2.7 x 10 V/m.
What is the kinetic energy of the electron just as it reaches the positive plate?
Electric field
Electron
KEpositive =
+ ++++ ...++
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