An electron is fired through a small hole in the positive plate of a parallel-plate capacitor at a speed of 1.1 x 107 m/s. The capacitor plates, which are in a vacuum chamber, are 1.8-cm-diameter disks spaced 3.0 mm apart. The electron travels 2.0 mm before being turned back. What is the capacitor's charge? Express your answer with the appropriate units. μA Q= Value Units ?

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Chapter1: Units, Trigonometry. And Vectors
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### Educational Content

**Physics Problem: Electron and Capacitor**

An electron is fired through a small hole in the positive plate of a parallel-plate capacitor at a speed of \(1.1 \times 10^7 \, \text{m/s}\). The capacitor plates, which are in a vacuum chamber, are 1.8-cm diameter disks spaced 3.0 mm apart. The electron travels 2.0 mm before being turned back.

**Part A**

- **Question:** What is the capacitor's charge?
- **Instructions:** Express your answer with the appropriate units.

**Input Section:**

- **Q =** [Enter the Value] [Select the Units]

**Actions:**

- Submit your answer using the "Submit" button.
- You can view previous attempts by selecting "Previous Answers."
- To request help, click on "Request Answer."

Use this information to solve the problem, determining the charge on the capacitor that results in the described motion of the electron.
Transcribed Image Text:### Educational Content **Physics Problem: Electron and Capacitor** An electron is fired through a small hole in the positive plate of a parallel-plate capacitor at a speed of \(1.1 \times 10^7 \, \text{m/s}\). The capacitor plates, which are in a vacuum chamber, are 1.8-cm diameter disks spaced 3.0 mm apart. The electron travels 2.0 mm before being turned back. **Part A** - **Question:** What is the capacitor's charge? - **Instructions:** Express your answer with the appropriate units. **Input Section:** - **Q =** [Enter the Value] [Select the Units] **Actions:** - Submit your answer using the "Submit" button. - You can view previous attempts by selecting "Previous Answers." - To request help, click on "Request Answer." Use this information to solve the problem, determining the charge on the capacitor that results in the described motion of the electron.
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