An electron in the n = 8 level of a CS+ jon emits a photon of wavelength 104 nm. %3D (a) What is the frequency of this photon in Hertz? (answer in 3 sig.figs.) Hz (b) What is the energy of this photon in Joules? (answer in 3 sig.figs.) () Would you expect the electron to move to a higher or lower energy level? (d) To what energy level does the electron move? n=

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An electron in the n = 8 level of a C* ion emits a photon of wavelength 104 nm.
Hz
(a) What is the frequency of this photon in Hertz? (answer in 3 sig.figs.)
(b) What is the energy of this photon in Joules? (answer in 3 sig.figs.)
() Would you expect the electron to move to a higher or lower energy level?
(d) To what energy level does the electron move? n=
Calculate the ionization energy (in kl/mol) for Al2t. (answer in 3 sig.figs.)
Answer:
kl/mol
Transcribed Image Text:An electron in the n = 8 level of a C* ion emits a photon of wavelength 104 nm. Hz (a) What is the frequency of this photon in Hertz? (answer in 3 sig.figs.) (b) What is the energy of this photon in Joules? (answer in 3 sig.figs.) () Would you expect the electron to move to a higher or lower energy level? (d) To what energy level does the electron move? n= Calculate the ionization energy (in kl/mol) for Al2t. (answer in 3 sig.figs.) Answer: kl/mol
Expert Solution
Step 1

Interpretation: An electron in the n=8 level of C5+ ion emits a photon of wavelength 104 nm. the frequency of this photon in hertz and the energy of this photon in joules are to be determined.

Step 2

Photons travel at the speed of light in a vacuum, 3.00×108m/s rounded to three significant figures. The relationship between speed of light (c), wavelength λ, and frequency ν is given mathematically as c = λ·ν

1) To find the frequency of photon with a wavelength of 104 nm,

ν = cλν = 3×108 m/s1.04×10-7m   = 2.88×1015 s-1   = 2.88×1015 Hz

Therefore, the frequency of photon is 2.88×1015 Hz.

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