Answered: An electron enters a region of space… | bartleby

Related questions

Question

100%

An electron enters a region of space containing a uniform 2.73 x 10-³ T magnetic field. Its speed is 125 m/s and it enters
perpendicularly to the field. Under these conditions, the electron undergoes circular motion. Find the radius r of the electron's
path and the frequency f of the motion.
r =
m
f =
Hz

Expert Solution

Step by step

Solved in 4 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

The two conducting rails in the drawing are tilted upward so they each make an angle of 30.0° with respect to the ground. The vertical magnetic field has a magnitude of 0.040 T. The 0.29-kg aluminum rod (length - 1.6 m) slides without friction down the rails at a constant velocity. How much current flows through the rod? Number i Conducting Units 16m-
A rod of mass 0.720 kg and radius 6.00 cm rests on two parallel rails (see figure below) that are d = 12.0 cm apart and L = 45.0 cm long. The rod carries a current of I = 70.0 A in the direction shown and rolls along the rails without slipping. A uniform magnetic field of magnitude 0.260 T is directed perpendicular to the rod and the rails. If it starts from rest, what is the speed of the rod as it leaves the rails? (Assume that the rod is of uniform density.) m/s L tea
In the figure shown below, the current in the long, straight wire is i₁ = 8.5 A, and the wire lies in the plane of the rectangular loop, which carries 1₂ = 7.5 A. The dimensions are a = 15 cm, b = 4.5 cm, and L = 21 cm. Find the magnitude and direction of the force exerted by the magnetic field due to the straight wire on the top and bottom segments of the loop. y L a b The force on the top segment: the magnitude, Ftop the force is directed Up The force on the bottom segment: = the magnitude, Fbottom= the force is directed Down Find the net force on the loop. i₂ The magnitude of the net force, Fnet the force is directed Down i₁ Units UN Units UN ✓✓. = Units UN " X
= A proton moves through a region containing a uniform electric field given by E 48.0 ĵ V/m and a uniform magnetic field B (0.200 î + 0.300 ĵ + 0.400 K) T. Determine the acceleration of the proton when it has a velocity ✓ = 170 î m/s. ↑ m/s² =
A proton is accelerated from rest through 2.0 kV. It then enters a uniform magnetic field of 0.30 T that is oriented perpendicular to its direction of motion. What is the radius of the path the proton follows in the magnetic field? O 11 cm O 11 mm O 22 cm O 1.1 m O 22 mm
An electron enters a region of space containing a uniform 2.21 × 10¬³ T magnetic field. Its speed is 173 m/s and it enters perpendicularly to the field. Under these conditions, the electron undergoes circular motion. Find the radius r of the electron's path and the frequency f of the motion. r = m f = Hz
An electron moves in a circle of radius r = 6.19 × 10-11 m with a speed 2.47 x 106 m/s. Treat the circular path as a current loop with a constant current equal to the ratio of the electron's charge magnitude to the period of the motion. If the circle lies in a uniform magnetic field of magnitude B = 6.04 mT, what is the maximum possible magnitude of the torque produced on the loop by the field? Number i Units
A particle of mass m and charge q is accelerated along the +x axis (in the plane of the page) from rest through an electric potential difference V. The particle then enters a region, defined by x > 0, containing a uniform magnetic field. y V = 400.0 V B = 0.850 T q = -1.602 × 10-19 C m = 6.68 × 10-27 kg V B = 0 8. When the particle first enters the region with the magnetic field the Lorentz force acting on it is directed along the +y axis. What is the direction of the Magnetic field? Explain your reasoning a. +z b. -z с. +x d. -x
A proton moves at 7.50 ✕ 107 m/s, perpendicular to a magnetic field. The field causes the proton to travel in a circular path of radius 0.840 m. What is the field strength?
A metal strip 6.70 cm long, 0.850 cm wide, and 0.880 mm thick moves with constant velocity in the positive y direction through a uniform magnetic field B = 2.30 mT that is directed in the negative z direction. A potential difference of 4.60 μV is measured across the width of the strip. What is the magnitude of the velocity v of the strip?
An electron (me = 9.11 x 1031 kg, q = -1.602 x 10-19 C) travels at 3.0 x 10' m/s perpendicular to a 1.2 mT magnetic field. What is the magnitude of the electron's acceleration in m/s? Give your answer as only the numerical value in the Sl units specified. e is interpreted as x10^ for use with large or small values; 1.01e2 is interpreted as 1.01 x 102.
Part A,C,E please A proton (q = 1.60×10^−19 C, m = 1.67×10^−27kg) moves in a uniform magnetic field B⃗=(0.530 T)i^. At t= 0 the proton has a velocity components vx= 2.00×10^5 m/s, vy=0, and vz= 2.00×10^5 m/s. Part A What is the magnitude of the magnetic force acting on the proton? Part C In addition to the magnetic field there is a uniform electric field in the +x-direction, E⃗=(2.00×10^4 V/m)i^. Will the proton have a component of acceleration in the direction of the electric field? Part E At t=T/2, where T is the period of the circular motion of the proton, what is the x-component of the displacement of the proton from its position at t=0?

SEE MORE QUESTIONS