None An electron configuration for aNiatom is: 1s22s22p 3s23p 4s23d and the orbital diagram in shown below. Write all four quantumnumbers for the electron specified (circled by green).1L1L1L 1L 1L1L1L1L 1L1L111s2s2p3s3p4s3dAn example of an answer.n=[type the number], =[type the number], me"[type the number], m,-[type the number].Use the editor to format your answerGive detailed Solution with explanation needed, don't giveHandwritten answer

To determine the quantum numbers for a specific electron in the electron configuration, follow these…

Answered: An electron configuration for aNiatom…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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determine the product
please answer clearly and circle answer. thanks
Is this answer correct? Pretty sure it is, but I just want to make sure :) Thanks!
s-sp³ = ??? =N
12
Research studies have found that the price elasticity of demand for bread is equal to -0.40 and the price elasticity of demand of butter is equal to -1.13. Holding everything else constant, if the price of bread and the price of butter each increase by 10 percent: (a) Will the revenue from sales of bread increase or decrease? (b) Will the revenue from sales of butter increase or decrease?
Use and modify some/all the reactions provided to form the indicated overall reaction according to Hess' Law. • If a reaction is not used in your Hess' Law process, include that indication by multiplying the reaction by "0" • If no modification is needed and the reaction is applied as written below, include that indication by multiplying the reaction by "1" • Use whole numbers and simple fractions (such as "2" or "1/2", not 0.5) and negative signs (such as "-2") where needed Then calculate and report the enthalpy change (in kJ) for the overall reaction in the indicated blank, including units with your written value and rounded to 1 decimal place. Overall Reaction: CS2(1) + 302(g) → CO2(g) + 2SO2(g) Rxn # Reaction ΔΗ° (kJ) 1 C(s) → C(g) 716.67 2 C(s) + O2(g) → CO2(g) -393.5 3 3Fe(s) +202(g) → Fe3O4(s) -1118 4 C(s) + 2S(s) → CS2(1) 87.9 5 CH4(g) + O2(g) → CO₂(g) + H₂O(g) -882.0 6 S(s) + O2(g) → SO2(g) -296.8 N2(g) + 4H2(g) + Cl2(g) → 2NH4Cl(g) -629.1 7
stru Wh
Given the following reactions Fe203(s) + 3CO(s) 2Fe(s) + 3CO2(g) AH = -28.0 kJ AH = +12.5 kJ 3Fe(s) + 4CO2(s) → 4CO2(g) + Fe3O4(s) + CO(g) → CO3(g) + 2FE3O4(s)- + 2FE304(s)' Determine the enthalpy of the reaction of Fe203 with CO: 3FE2O3(s) Answer:
t- U- S- 요 s O NHẠCH3, H® NHE+₂, HⓇ CN Ⓒ ΝΗ, Η
ORT SHEET Heat of Neutralization EXPERIMENT elemsboomfchg lom 12 A. Heat Capacity of Calorimeter 1. Temp. of calorimeter and water before mixing 2. Temp. of warm water °C 22.0 39,0 30.3 3. Maximum temp. determined from your curve °C 4. Heat lost by warm water (temp decrease x °C 50.0 g x 4.184 J/K-g) = 02), 5. Heat gained by cooler water (temp. increase x 50.0 g x 4.184 J/K-g) = 30,3 22.0)x 13626J s0.0gmpi S0.0gy 6. Heat gained by the calorimeter [(4) – (5)] = 7. Heat capacity of calorimeter: heat gained by the calorimeter temperature increase J/K 3. Heat of Neutralization of HCl-NaOH 22.2 22.2. °C . Temp. of calorimeter and NaOH Temp. of HCI AT determined from your curve after adding HC1 °C to the NaOH Heat gained by solution (temperature increase x ON 100 g x 4.184 J/K-g) = 9977.8J %3D Heat gained by calorimeter (temperature increase x heat capacity of calorimeter) = J %3D Total joules released by reaction [(3) + (4)] = Tight O 2018 Pearson Education, Inc.
Is 10b more than one product? Not sure the way it is written.

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