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An electromotive force 240, 0 ≤t≤ 50 E(t) 10, t > 50 is applied to an LR-series circuit in which the inductance is 30 henries and the resistance is 3 ohms. Find the current i(t) if i(0) = 0. 80 – 80e -() 0 ≤ t≤ 50 i(t) = t (80e4–80) e 2 20 ' t> 50

An electromotive force 240, 0 ≤t≤ 50 E(t) 10, t > 50 is applied to an LR-series circuit in which the inductance is 30 henries and the resistance is 3 ohms. Find the current i(t) if i(0) = 0. 80 – 80e -() 0 ≤ t≤ 50 i(t) = t (80e4–80) e 2 20 ' t> 50

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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An electromotive force 240, 0 ≤t≤ 50 E(t) 10, t > 50 is applied to an LR-series circuit in which the inductance is 30 henries and the resistance is 3 ohms. Find the current i(t) if i(0) = 0. 80 – 80e -() 0 ≤ t≤ 50 i(t) = t (80e4–80) e 2 20 ' t> 50
Transcribed Image Text:An electromotive force 240, 0 ≤t≤ 50 E(t) 10, t > 50 is applied to an LR-series circuit in which the inductance is 30 henries and the resistance is 3 ohms. Find the current i(t) if i(0) = 0. 80 – 80e -() 0 ≤ t≤ 50 i(t) = t (80e4–80) e 2 20 ' t> 50
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