An electric utility company determines the monthly bill by charging 85.4 cents per kilowatt-hour (kWh) used plus a base charge of $17.55 per month. Thus, the monthly charge is given by the function f(W)=0.854W+17.55 dollars, where W is the number of kilowatt-hours. a. Find f (6000) and explain what it means. b. What is the monthly charge if 9500 kWh are used?
An electric utility company determines the monthly bill by charging 85.4 cents per kilowatt-hour (kWh) used plus a base charge of $17.55 per month. Thus, the monthly charge is given by the function f(W)=0.854W+17.55 dollars, where W is the number of kilowatt-hours. a. Find f (6000) and explain what it means. b. What is the monthly charge if 9500 kWh are used?
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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An electric utility company determines the monthly bill by charging
85.4
cents per kilowatt-hour (kWh) used plus a base charge of
$17.55
per month. Thus, the monthly charge is given by the function
f(W)=0.854W+17.55
dollars, where W is the number of kilowatt-hours.a. Find f
(6000)
and explain what it means.b. What is the monthly charge if
9500
kWh are used?a. Select the correct choice below and fill in the answer box to complete your choice.
(Simplify your answers. Type integers or decimals.)
f(6000)=nothing.
The charge for
6000
kWh is
$nothing.
f(6000)=nothing.
The charge for
nothing
kWh is
$6000.
b. The monthly charge is
$nothing
if
9500
kWh are used.(Simplify your answer. Type an integer or a decimal.)
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