An electric circuit has a battery with an EMF of 1.50 V. Its positive terminal is connected to its negative terminal by a copper wire in a circular loop having a radius of 0.500 m. Solve for the drift velocity in the wire if there is one free electron per copper atom. Detailed assumptions: - The size of the cell is negligible compared to the length of the circuit. - Copper resistivity: p = 1.80x10-®N – m - Copper density: D = 8.96x10³ kg – m-3 Copper relative atomic mass: m, = 63.5 g/mol
An electric circuit has a battery with an EMF of 1.50 V. Its positive terminal is connected to its negative terminal by a copper wire in a circular loop having a radius of 0.500 m. Solve for the drift velocity in the wire if there is one free electron per copper atom. Detailed assumptions: - The size of the cell is negligible compared to the length of the circuit. - Copper resistivity: p = 1.80x10-®N – m - Copper density: D = 8.96x10³ kg – m-3 Copper relative atomic mass: m, = 63.5 g/mol
University Physics Volume 1
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Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter1: Units And Measurement
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Problem 65P: A floating-point operation is a single arithmetic operation such as addition, subtraction,...
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![INSTRUCTIONS:
Show your complete solution to each problem on a short bond paper.
Answers must be expressed in engineering notation (when the exponent of the base 10 multiplier
is not a multiple of 3, press ENG or SHIFT+ENG, whichever the case.)
Example: 0.06N or 6.0x10-2 N must be expressed to 60x103 N or 60mN](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F06bf52e7-a328-49ff-a4f1-df03d78f9a69%2F695e40cf-66d8-49db-8ef1-68600f372205%2Fvr9oqgi_processed.png&w=3840&q=75)
Transcribed Image Text:INSTRUCTIONS:
Show your complete solution to each problem on a short bond paper.
Answers must be expressed in engineering notation (when the exponent of the base 10 multiplier
is not a multiple of 3, press ENG or SHIFT+ENG, whichever the case.)
Example: 0.06N or 6.0x10-2 N must be expressed to 60x103 N or 60mN
![An electric circuit has a battery with an EMF of 1.50 V. Its positive terminal is connected to its negative
terminal by a copper wire in a circular loop having a radius of 0.500 m. Solve for the drift velocity in the wire
if there is one free electron per copper atom.
Detailed assumptions:
- The size of the cell is negligible compared to the length of the circuit.
- Copper resistivity: p = 1.80x10-80 – m
- Copper density: D = 8.96x10³ kg – m-3
- Copper relative atomic mass: m, = 63.5 g/mol](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F06bf52e7-a328-49ff-a4f1-df03d78f9a69%2F695e40cf-66d8-49db-8ef1-68600f372205%2Ffmw9bib_processed.png&w=3840&q=75)
Transcribed Image Text:An electric circuit has a battery with an EMF of 1.50 V. Its positive terminal is connected to its negative
terminal by a copper wire in a circular loop having a radius of 0.500 m. Solve for the drift velocity in the wire
if there is one free electron per copper atom.
Detailed assumptions:
- The size of the cell is negligible compared to the length of the circuit.
- Copper resistivity: p = 1.80x10-80 – m
- Copper density: D = 8.96x10³ kg – m-3
- Copper relative atomic mass: m, = 63.5 g/mol
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