3. The time to half-maximum voltage is how long it takes the capacitor to charge halfway. Based on your experimental results, how long does it take the capacitor to charge to 75% of its maximum? 4. After four "half-lives" (i.e., time to half-max), to what percentage of the maximum charge is the capacitor charged?
3. The time to half-maximum voltage is how long it takes the capacitor to charge halfway. Based on your experimental results, how long does it take the capacitor to charge to 75% of its maximum? 4. After four "half-lives" (i.e., time to half-max), to what percentage of the maximum charge is the capacitor charged?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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I want to solve the questions referred to✏️
![Exp-1 RC circuit - Word
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Data
9.88sec
| 6.685 see
0.205 See
Time (ti)
Vo =4.076V
Time (t2)
° =2·038V
Time to half
max
(11/2) = t2 - ti
Calculation
Calculate the capacitance of the capacifor: o.085-9.88=6:205
1.
t, = rin 2= RC In 2= RC (0.693)
6.205
jooo (6.693) =295.8X 10
295. 8xis ba5.8
= 2;158 X10'F
C=
R(U.693)
Capacitance
(C)
Determine the percent difference between the calculated capacitance and the
value on the capacitor (330 µF):
|calculated - 330 uF
%diff =
2.
x100%
330uF
(2958-330)00=-1036%
330
-- 10
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Transcribed Image Text:Exp-1 RC circuit - Word
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Name
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Data
9.88sec
| 6.685 see
0.205 See
Time (ti)
Vo =4.076V
Time (t2)
° =2·038V
Time to half
max
(11/2) = t2 - ti
Calculation
Calculate the capacitance of the capacifor: o.085-9.88=6:205
1.
t, = rin 2= RC In 2= RC (0.693)
6.205
jooo (6.693) =295.8X 10
295. 8xis ba5.8
= 2;158 X10'F
C=
R(U.693)
Capacitance
(C)
Determine the percent difference between the calculated capacitance and the
value on the capacitor (330 µF):
|calculated - 330 uF
%diff =
2.
x100%
330uF
(2958-330)00=-1036%
330
-- 10
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10:39 AM
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近
![Calculation
1. Calculate the capacitance of the capacitor:
t, =t In2 = RC In 2 = RC (0.693)
C =
R(0.693)
Capacitance
(С)
2. Determine the percent difference between the calculated
capacitance and the value on the capacitor (330 µF):
calculated - 330µF|
%diff =
x 100%
330µF
Questions
3. The time to half-maximum voltage is how long it takes the
capacitor to charge halfway. Based on your experimental
results, how long does it take the capacitor to charge to
75% of its maximum?
4. After four “half-lives" (i.e., time to half-max), to what
percentage of the maximum charge is the capacitor
charged?
5. What is the maximum charge for the capacitor in this
experiment?
6. What are some factors that could account for the percent
difference between the stated and experimental values?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F51c49522-7e3e-4318-a2d2-27dd1886e4c2%2F317efe51-7171-474b-a502-c9f9777bb18f%2F0qpop9b_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Calculation
1. Calculate the capacitance of the capacitor:
t, =t In2 = RC In 2 = RC (0.693)
C =
R(0.693)
Capacitance
(С)
2. Determine the percent difference between the calculated
capacitance and the value on the capacitor (330 µF):
calculated - 330µF|
%diff =
x 100%
330µF
Questions
3. The time to half-maximum voltage is how long it takes the
capacitor to charge halfway. Based on your experimental
results, how long does it take the capacitor to charge to
75% of its maximum?
4. After four “half-lives" (i.e., time to half-max), to what
percentage of the maximum charge is the capacitor
charged?
5. What is the maximum charge for the capacitor in this
experiment?
6. What are some factors that could account for the percent
difference between the stated and experimental values?
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