3. The time to half-maximum voltage is how long it takes the capacitor to charge halfway. Based on your experimental results, how long does it take the capacitor to charge to 75% of its maximum? 4. After four "half-lives" (i.e., time to half-max), to what percentage of the maximum charge is the capacitor charged?

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Exp-1 RC circuit - Word
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Data
9.88sec
| 6.685 see
0.205 See
Time (ti)
Vo =4.076V
Time (t2)
° =2·038V
Time to half
max
(11/2) = t2 - ti
Calculation
Calculate the capacitance of the capacifor: o.085-9.88=6:205
1.
t, = rin 2= RC In 2= RC (0.693)
6.205
jooo (6.693) =295.8X 10
295. 8xis ba5.8
= 2;158 X10'F
C=
R(U.693)
Capacitance
(C)
Determine the percent difference between the calculated capacitance and the
value on the capacitor (330 µF):
|calculated - 330 uF
%diff =
2.
x100%
330uF
(2958-330)00=-1036%
330
-- 10
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149 words
70%
10:39 AM
P Type here to search
2/10/2021
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Transcribed Image Text:Exp-1 RC circuit - Word Ink Tools File Home Insert Design Layout References Mailings Review View Pens O Tell me what you want to do... Sign in 2 Share Color Thickness Pen Highlighter Eraser Select Objects Ink to Stop Math Inking Write Pens Convert Close Name Abid Data 9.88sec | 6.685 see 0.205 See Time (ti) Vo =4.076V Time (t2) ° =2·038V Time to half max (11/2) = t2 - ti Calculation Calculate the capacitance of the capacifor: o.085-9.88=6:205 1. t, = rin 2= RC In 2= RC (0.693) 6.205 jooo (6.693) =295.8X 10 295. 8xis ba5.8 = 2;158 X10'F C= R(U.693) Capacitance (C) Determine the percent difference between the calculated capacitance and the value on the capacitor (330 µF): |calculated - 330 uF %diff = 2. x100% 330uF (2958-330)00=-1036% 330 -- 10 Page 1 of 2 149 words 70% 10:39 AM P Type here to search 2/10/2021 近
Calculation
1. Calculate the capacitance of the capacitor:
t, =t In2 = RC In 2 = RC (0.693)
C =
R(0.693)
Capacitance
(С)
2. Determine the percent difference between the calculated
capacitance and the value on the capacitor (330 µF):
calculated - 330µF|
%diff =
x 100%
330µF
Questions
3. The time to half-maximum voltage is how long it takes the
capacitor to charge halfway. Based on your experimental
results, how long does it take the capacitor to charge to
75% of its maximum?
4. After four “half-lives" (i.e., time to half-max), to what
percentage of the maximum charge is the capacitor
charged?
5. What is the maximum charge for the capacitor in this
experiment?
6. What are some factors that could account for the percent
difference between the stated and experimental values?
Transcribed Image Text:Calculation 1. Calculate the capacitance of the capacitor: t, =t In2 = RC In 2 = RC (0.693) C = R(0.693) Capacitance (С) 2. Determine the percent difference between the calculated capacitance and the value on the capacitor (330 µF): calculated - 330µF| %diff = x 100% 330µF Questions 3. The time to half-maximum voltage is how long it takes the capacitor to charge halfway. Based on your experimental results, how long does it take the capacitor to charge to 75% of its maximum? 4. After four “half-lives" (i.e., time to half-max), to what percentage of the maximum charge is the capacitor charged? 5. What is the maximum charge for the capacitor in this experiment? 6. What are some factors that could account for the percent difference between the stated and experimental values?
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