for image 2:Part (a) Calculate the magnitude of the velocity of the fish relative to the water when it hits the water in m/s. v=Part (b) Calculate the angle, in degrees, by which the fish's velocity is directed below the horizontal when the fish hits the water. θ= **Physics Problem: Horizontal Motion and Free Fall**An eagle is flying horizontally at a speed of **2.8 m/s** when the fish in her talons wiggles loose and falls into the lake **5.8 m** below.*Problem Explanation:*This problem involves two key concepts in physics: horizontal motion and free fall under gravity. When the fish wiggles free from the eagle's talons, it continues to move horizontally at the same speed as the eagle (2.8 m/s) due to inertia, while simultaneously falling vertically due to gravity. The fish's vertical motion can be analyzed using the equations of motion under constant acceleration due to gravity.*Key Points to Consider:*1. **Horizontal Motion:** The fish maintains a horizontal velocity of 2.8 m/s until it hits the water.2. **Vertical Motion:** The fish falls from a height of 5.8 meters. The fall is influenced by the gravitational acceleration, which is approximately 9.81 m/s².*Graphs and Diagrams:*There are no graphs or diagrams included in this text. However, to solve this problem or illustrate the concepts, one could include:- A diagram showing the eagle flying and the path of the fish as it falls.- A graph plotting the horizontal position versus time and vertical position versus time of the fish.*Math Formulation:*- Horizontal distance traveled: \( d = v \times t \), where \( v \) is the horizontal velocity (2.8 m/s) and \( t \) is the time.- Time to fall: Derived from the equation \( h = \frac{1}{2} g t^2 \), where \( h \) is the height (5.8 m) and \( g \) is the acceleration due to gravity (9.81 m/s²).By solving these equations, students can determine both the duration of the fall and the horizontal distance traveled by the fish during its descent.*Educational Purpose:*This example helps in understanding the principles of kinematics, specifically the independence of horizontal and vertical components of motion in physics. **Physics Problem: Projectile Motion***Suppose a goalkeeper can give the ball a speed of 25 m/s.***Question:**What is the maximum horizontal distance the ball could go in meters?\[ R = \_\_\_\_\_\_\_\_\_\_\_\_\_ \]**Explanation:**To solve this problem, you will need to use the principles of projectile motion. The maximum horizontal distance (Range) \( R \) is achieved when the projectile is launched at an angle of 45 degrees to the horizontal. The formula to calculate the range is:\[ R = \frac{v^2 \sin(2\theta)}{g} \]Where:- \( v \) is the initial velocity of the ball (25 m/s in this case),- \( \theta \) is the launch angle (45 degrees for maximum range),- \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)).Substitute the values into the formula to find the maximum horizontal distance \( R \).

Name: for image 2:Part (a) Calculate the magnitude of the velocity of the f
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Description: for image 2:Part (a) Calculate the magnitude of the velocity of the fish relative to the water when it hits the water in m/s. v=Part (b) Calculate the angle, in degrees, by which the fish's velocity is directed below the horizontal when the fish hi