An automobile tire is filled with air at a pressure of 27.0 lb/in² at 25°C. A cold front moves through and the temperature drops to 5°C. Assuming no change in volume, what is the new tire pressure?
An automobile tire is filled with air at a pressure of 27.0 lb/in² at 25°C. A cold front moves through and the temperature drops to 5°C. Assuming no change in volume, what is the new tire pressure?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Problem Statement:**
An automobile tire is filled with air at a pressure of 27.0 lb/in² at 25°C. A cold front moves through and the temperature drops to 5°C. Assuming no change in volume, what is the new tire pressure?
**Explanation:**
This problem involves the relationship between pressure and temperature in gases, known as Gay-Lussac's Law. The law states that the pressure of a gas is directly proportional to its absolute temperature when volume remains constant. The formula is:
\[ P_1/T_1 = P_2/T_2 \]
Where:
- \( P_1 \) = initial pressure
- \( T_1 \) = initial temperature in Kelvin
- \( P_2 \) = final pressure
- \( T_2 \) = final temperature in Kelvin
**Solution Steps:**
1. Convert temperatures from Celsius to Kelvin:
- \( T_1 = 25°C + 273.15 = 298.15 K \)
- \( T_2 = 5°C + 273.15 = 278.15 K \)
2. Use the formula \[ P_1/T_1 = P_2/T_2 \] to solve for \( P_2 \):
- Rearrange to find \( P_2 \):
\[ P_2 = P_1 \times (T_2/T_1) \]
- Substitute known values:
\[ P_2 = 27.0 \, \text{lb/in}^2 \times \left(\frac{278.15}{298.15}\right) \]
3. Calculate \( P_2 \).
Thus, the new tire pressure can be calculated based on the provided initial conditions and the temperature change.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7e96488f-32f6-404a-ba45-c56daf4e94fd%2F2773efc8-8c78-4dbb-8c2b-69afcd85e785%2Fyachqb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
An automobile tire is filled with air at a pressure of 27.0 lb/in² at 25°C. A cold front moves through and the temperature drops to 5°C. Assuming no change in volume, what is the new tire pressure?
**Explanation:**
This problem involves the relationship between pressure and temperature in gases, known as Gay-Lussac's Law. The law states that the pressure of a gas is directly proportional to its absolute temperature when volume remains constant. The formula is:
\[ P_1/T_1 = P_2/T_2 \]
Where:
- \( P_1 \) = initial pressure
- \( T_1 \) = initial temperature in Kelvin
- \( P_2 \) = final pressure
- \( T_2 \) = final temperature in Kelvin
**Solution Steps:**
1. Convert temperatures from Celsius to Kelvin:
- \( T_1 = 25°C + 273.15 = 298.15 K \)
- \( T_2 = 5°C + 273.15 = 278.15 K \)
2. Use the formula \[ P_1/T_1 = P_2/T_2 \] to solve for \( P_2 \):
- Rearrange to find \( P_2 \):
\[ P_2 = P_1 \times (T_2/T_1) \]
- Substitute known values:
\[ P_2 = 27.0 \, \text{lb/in}^2 \times \left(\frac{278.15}{298.15}\right) \]
3. Calculate \( P_2 \).
Thus, the new tire pressure can be calculated based on the provided initial conditions and the temperature change.
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