An automobile tire is filled with air at a pressure of 27.0 lb/in² at 25°C. A cold front moves through and the temperature drops to 5°C. Assuming no change in volume, what is the new tire pressure?

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**Problem Statement:**

An automobile tire is filled with air at a pressure of 27.0 lb/in² at 25°C. A cold front moves through and the temperature drops to 5°C. Assuming no change in volume, what is the new tire pressure?

**Explanation:**

This problem involves the relationship between pressure and temperature in gases, known as Gay-Lussac's Law. The law states that the pressure of a gas is directly proportional to its absolute temperature when volume remains constant. The formula is:

\[ P_1/T_1 = P_2/T_2 \]

Where:
- \( P_1 \) = initial pressure
- \( T_1 \) = initial temperature in Kelvin
- \( P_2 \) = final pressure
- \( T_2 \) = final temperature in Kelvin

**Solution Steps:**

1. Convert temperatures from Celsius to Kelvin:
   - \( T_1 = 25°C + 273.15 = 298.15 K \)
   - \( T_2 = 5°C + 273.15 = 278.15 K \)

2. Use the formula \[ P_1/T_1 = P_2/T_2 \] to solve for \( P_2 \):
   - Rearrange to find \( P_2 \): 
     \[ P_2 = P_1 \times (T_2/T_1) \]
   - Substitute known values:
     \[ P_2 = 27.0 \, \text{lb/in}^2 \times \left(\frac{278.15}{298.15}\right) \]

3. Calculate \( P_2 \).

Thus, the new tire pressure can be calculated based on the provided initial conditions and the temperature change.
Transcribed Image Text:**Problem Statement:** An automobile tire is filled with air at a pressure of 27.0 lb/in² at 25°C. A cold front moves through and the temperature drops to 5°C. Assuming no change in volume, what is the new tire pressure? **Explanation:** This problem involves the relationship between pressure and temperature in gases, known as Gay-Lussac's Law. The law states that the pressure of a gas is directly proportional to its absolute temperature when volume remains constant. The formula is: \[ P_1/T_1 = P_2/T_2 \] Where: - \( P_1 \) = initial pressure - \( T_1 \) = initial temperature in Kelvin - \( P_2 \) = final pressure - \( T_2 \) = final temperature in Kelvin **Solution Steps:** 1. Convert temperatures from Celsius to Kelvin: - \( T_1 = 25°C + 273.15 = 298.15 K \) - \( T_2 = 5°C + 273.15 = 278.15 K \) 2. Use the formula \[ P_1/T_1 = P_2/T_2 \] to solve for \( P_2 \): - Rearrange to find \( P_2 \): \[ P_2 = P_1 \times (T_2/T_1) \] - Substitute known values: \[ P_2 = 27.0 \, \text{lb/in}^2 \times \left(\frac{278.15}{298.15}\right) \] 3. Calculate \( P_2 \). Thus, the new tire pressure can be calculated based on the provided initial conditions and the temperature change.
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