Example 6.1Need Help?An automobile manufacturer has developed a new type of bumper, which is supposed to absorb impacts withless damage than previous bumpers. The manufacturer has used this bumper in a sequence of 25 controlledcrashes against a wall, each at 10 mph, using one of its compact car models. Let X = the number of crashes thatresult in no visible damage to the automobile. The ---Select---to be estimated is p = the ---Select--- Cof all such crashes that result in no damage [alternatively, p = P(no damage in a single crash)]. If X is observedto be x = 14, the most reasonable estimator and estimate areestimator pRead Itnestimate =Xn

Given that, an automobile manufacturer has developed a new type of bumper, which is supposed to…

Answered: An automobile manufacturer has…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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A researcher claims that a post-lunch nap decreases the amount of time it takes males to sprint 20 meters after a night with only 4 hours of sleep. The table shows the amounts of time (in seconds) it took for 10 males to sprint 20 meters after a night with only 4 hours of sleep when they did not take a post-lunch nap and when they did take a post-lunch nap. At a 0.01, is there enough evidence to support the researcher's claim? Assume the samples are random and dependent, and the population is normally distributed. Complete parts (a) through (e) below. Male Sprint time (without 1 5 4.01 3.93 3.95 4.05 3.00 4.06 3.93 4.05 3.97 3.05 Sprint time (with nap) 4.00 3.03 3.04 4.05 3.03 4.04 3.94 4.02 3.00 3.92 (a) Identify the claim and state Ho and H₂- What is the claim? A A post-lunch nap decreases the amount of time it takes males to sprint 20 meters OB. A post-lunch nap increases the amount of time it takes males to sprint 20 meters OC. A night with only 4 hours of sleep increases the…
A sample of 900 commuters from New York were interviewed randomly and 416 answered they like express trains. Determine if the sample evidence shows that less than half of the commuters like express trains. Use α=0.05.
A manufacturer claims that it has increased the shelf life of a line of cake mixes. Past records indicate that the average shelf life of the mix is 216 days. After a revised mix has been developed, a sample of six boxes of cake mix gave these shelf lives (in days): 215, 217, 218, 219, 216, and 217.Using α = 0.05, test the manufacturer claim that the shelf life of the cake mix is more than 216 days. a- Standard Deviation b- Testing a mean, Calculated c- Critical mean, Table d- p-value e-What do we conclude?
For the population, 57% of people are searched if stopped. For a sample of 26441 stops, what Z-test value is calculated given Black men are searched 61% of the time when stopped?
Before every flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the aircraft. The aircraft can carry 42 passengers, and a flight has fuel and baggage that allows for the total passenger load of 6,972lb. The pilot sees that the plane is full and all the passengers are men. The aircraft will be overloaded if the mean weight of the passengers is greater than 6,972lb/42=166lb. What is the probability that the aircraft is overloaded? Should the pilot take any action to correct for an overloaded aircraft? Assume that the weights of men are normally distributed with a mean of 176.9lb and a standard deviation of 37.7. THE probability is approximately. ? Round to four decimal places.
A researcher selected a sample of 268 former student-athletes from a list of graduates of a large university. A total of 14% of the sample of athletes had earned graduate degrees as compared to 17% of all graduates. What is the Z obtained value?
The authors of a paper compared two different methods for measuring body fat percentage. One method uses ultrasound, and the other method uses X-ray technology. The table gives body fat percentages for 16 athletes using each of these methods (a subset of the data given in a graph that appeared in the paper). For purposes of this exercise, you can assume that the 16 athletes who participated in this study are representative of the population of athletes. Athlete 0 Ho: Md = Ha: Md 0 < 0 5 6 7 8 9 10 11 12 13 14 15 16 X-ray 4.75 7.00 9.25 12.00 17.25 29.50 5.50 6.00 8.00 8.50 9.25 11.00 12.00 14.00 17.00 18.00 USE SALT Ultrasound 4.75 4.00 9.00 11.75 17.00 27.75 6.50 6.75 8.75 9.75 9.50 12.00 12.25 15.75 18.00 18.50 X Find the test statistic and P-value. (Use a table or SALT. Round your test statistic to one decimal place and your P-value to three decimal places.) t = P-value = 0.000 Mx-ray ultrasound.)
A study was conducted at a local college to analyze the average cumulative GPA of students who graduated last year. Which of these terms is used to refer to: the average cumulative GPA of students in the study who graduated from the college last year?
A researcher designed a study to test whether caffeine use enhanced performance time to run a 100 meter sprint. The participants (n=30) ran a 100 meter sprint before the consumption of caffeine on day 1 and then they ran another 100 meter sprint on the following day 2 after ingesting caffeine. The average time taken to run the 100 meter sprint on day 1 was (M1) and the average to run on day 2 after caffeine was (M2). The variance for this study was calculated to be (S2). Does caffeine use improve the running time in the 100 meter sprint (e.g., lower time)? Use all of the data provided to you below and test at an alpha of 0.05. M1 = 26.53M2 = 14.69S2 = 207.75n=30 a) state null and alternate hypothesis b) what is the critical value c) what is the obtained value d) conclusion
A researcher claims that a post-lunch nap decreases the amount of time it takes males to sprint 20 meters after a night with only 4 hours of sleep. The table shows the amounts of time (in seconds) it took for 10 males to sprint 20 meters after a night with only 4 hours of sleep when they did not take a post-lunch nap and when they did take a post-lunch nap. At a = 0.10, is there enough evidence to support the researcher's claim? Assume the samples are random and dependent, and the population is normally distributed. Complete parts (a) through (e) below. Male 1 2 4 6 7 8 9 10 Sprint time (without nap) Sprint time (with nap) 4.07 3.95 3.95 4.04 4.02 | 4.09 4.06 3.96 3.95 3.93 3.92 3.86 3.88 3.97 4.01 4.00 3.90 3.82 3.86 3.80 A. t 1.383 C. t (c) Calculate d and sg. d= j = 0.1 (Round to three decimal places as needed.) Calculate sa. = 0.045 (Round to three decimal places as needed.) (d) Find the standardized test statistic t. t = 6.666 (Round to three decimal places as needed.) (e) Decide…

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