Question 1 of 10, Step 1 of 1CorrectIncorrectAn automobile manufacturer claims that its car has a 46.9 miles/gallon (MPG) rating. An independent testing firm has been contracted to test the MPG for this car sinceit is believed that the car has an incorrect manufacturer's MPG rating. After testing 150 cars, they found a mean MPG of 47.0. Assume the standard deviation is knownto be 1.1. A level of significance of 0.02 will be used. State the hypotheses.Enter the hypotheses:田 TablesE KeypadAnswerKeyboard ShortcutsHo:HTutorSkipTry SimilarSubmit AnswerO 2020 Hawkes LearningMacBook Air80888DIIDOescF1F2F3FSF7F10F11F12!@%23&145789%3Ddelete{}QWERTYUPtabASGH.JKcaps lockretur?CVMshiftcontroloptioncommandcommandoption

Name: Question 1 of 10, Step 1 of 1CorrectIncorrectAn automobile manufactur
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: Question 1 of 10, Step 1 of 1CorrectIncorrectAn automobile manufacturer claims that its car has a 46.9 miles/gallon (MPG) rating. An independent testing firm has been contracted to test the MPG for this car sinceit is believed that the car has an in

Given Information: Manufacturer claims that its car has 46.9 miles/gallon. (MPG) rating. i.e., hypothesized value μ0 = 46.9 It is believed that the manufacturer's rating is incorrect. To state the hypothesis: Let μ denotes the average rating of the car. Formulate the hypothesis as follows: Null Hypothesis: H0:μ=46.9 i.e., the manufacturer's rating is correct, the car has 46.9 miles/gallon. (MPG) rating. Alternative Hypothesis: Ha:μ≠46.9 i.e., the manufacturer's rating is incorrect, the car's rating is not equal to 46.9 miles/gallon. Therefore, the hypothesis are as follows: H0:μ=46.9 Ha:μ≠46.9

Math

Statistics

An automobile manufacturer daims that its car has a 46.9 miles/gallon (MPG) rating. An independent testing firm has been contracted to test thei it is believed that the car has an incorrect manufacturer's MPG rating. After testing 150 cars, they found a mean MPG of 47.0. Assume the standar to be 1.1. A level of significance of 0.02 will be used. State the hypotheses. Enter the hypotheses: O Tabl Answer Ho H

An automobile manufacturer daims that its car has a 46.9 miles/gallon (MPG) rating. An independent testing firm has been contracted to test thei it is believed that the car has an incorrect manufacturer's MPG rating. After testing 150 cars, they found a mean MPG of 47.0. Assume the standar to be 1.1. A level of significance of 0.02 will be used. State the hypotheses. Enter the hypotheses: O Tabl Answer Ho H

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

It is commonly believed that the mean body temperature of a healthy adult is 98.6° F. You are not entirely convinced. You believe thar it is not 98.6° F. You collected data using 46 healthy people and found that they had a mean body temperature of 98.31° Fwith a standard deviaiton of 0.95°F. Use a 0.10 significance level to test the claim that the mean body temperature of a healthy adult is not 98.6° F. a) Identify the null and alternative hypotheses? Ho: V H1:[ b) What type of hypothesis test should you conduct (left, right, or two-tailed)? Oleft-tailed Oright-tailed Otwo-tailed c) ldentify the appropriate significance level. d) Calculate your test statistic. Write the result below, and be sure to round your final answer to two decimal places.
The accompanying data set includes volumes (ounces) of a sample of cans of regular Coke. The summary statistics are n=36, x=12.192 oz, s=0.096 oz. Assume that a simple random sample has been selected. Use a 0.01 significance level to test the claim that cans of Coke have a mean volume of 12.00 ounces. Does it appear that consumers are being cheated? Click the icon to view the data set of regular Coke can volumes. Identify the null and alternative hypotheses. Ho H₁: (Type integers or decimals. Do not round.)
The U.S. Department of Energy reported that 51.7% of homes were heated by natural gas. A random sample of 221 homes in Kentucky found that 115 were heated by natural gas. Does the evidence support the claim for Kentucky at the a = 0.05 level? Are the results applicable across the country? Why?
QUESTION 2 Solve this Central Limit Theorem problem. Round the standard error to the nearest thousandth and the z-score to the nearest hundredth whenever necessary. An analyst at a cell phone company finds that for those who exceed the minutes included in their basic contract, the extra time used has a mean of u = 22 minutes and a standard deviation of o = 9 minutes. Beatrice finds a SRS of 60 customers who used extra minutes. Use the CLT to determine p(x s 24.5 minutes). %3D %3D Work: Ox = Work: Z = Work: Which image below (A, B, C, or D) looks most similar to the curve you drew? A B C D Area on Table: Final Answer: Work:
According to a survey conducted by the Association for Dressings and Sauces, 20% of American adults eat salad once a week. A nutritionist suspects that this percentage is not accurate. She conducts a survey of 579 American adults and finds that 104 of them eat salad once a week. Use a 0.10 significance level to test the claim that the proportion of American adults who eat salad once a week is equal to 20%. Claim: p = 0.2 v which corresponds to H0: p = 0.2 Opposite: p 0.2 v which corresponds to H1 p + 0.2 The test is: right-tailed The test statistic is: z= (to 2 decimals) The Critical Value is: z= Based on this we: Fail to reject the null hypothesis v Conclusion: There does not proportion of American adults who eat salad once a week is equal to 20%. v appear to be enough evidence to support the claim that the Submit Question thing 近

In the population of senior students at Shermer High School, the proportion who plan to attend college is 0.64. In a random sample of 100 students from this population, the proportion who plan to attend college is 0.75. We would call the value 0.64 a P-value. z-score. parameter statistic significance level.
The manufacturer claims that your new car gets 32 mpg on the highway. You suspect that the mpg is more for your car. The 69 trips on the highway that you took averaged 35.7 mpg and the standard deviation for these 69 trips was 12.4 mpg. What can be concluded at the αα = 0.05 level of significance? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: H0:H0: ? p μ Select an answer ≠ = < > H1:H1: ? μ p Select an answer ≠ > = < The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject fail to reject accept the null hypothesis. Thus, the final conclusion is that ... The data suggest that the population mean is not significantly more than 32 at αα = 0.05, so there is statistically insignificant…
Cadmium, a heavy metal, is toxic to animals. Mushrooms, however, are able to absorb and accumulate cadmium at high concentrations. Some governments have a safety limit for cadmium in dry vegetables at 0.56 part per million (ppm). A research team measured the cadmium levels in a random sample of edible mushrooms, where the hypothesis test is to decide whether the mean cadmium level in the sample is greater than the governments' safety limit. The null and alternative hypotheses are H0: μ=0.56 ppm, Ha: μ>0.56 ppm. Complete parts (a) through (e) below. d. Now suppose that the results of carrying out the hypothesis test lead to nonrejection of the null hypothesis. Classify that conclusion by error type or as a correct decision if in fact the mean cadmium level in that type of mushrooms equals the safety limit of 0.56 ppm. Choose the correct answer below. A. type I error B. correct decision because a true null hypothesis is not rejected C. correct decision because…
The EPA tests cars for city miles per gallon (mpg). For one model, a sample of 16 cars were tested for mpg, the results follow. 28 25.7 25.8 28 28.5 29.8 30.2 30.4 26.9 28.3 29.8 27.2 26.7 27.7 29.5 28 1) What is point estimate of the mean mpg?
The data found below measure the amounts of greenhouse gas emissions from three types of vehicles. The measurements are in tons per year, expressed as CO2 equivalents. Use a 0.025 significance level to test the claim that the different types of vehicle have the same mean amount of greenhouse gas emissions. Based on the results, does the type of vehicle appear to affect the amount of greenhouse gas emissions? Click the icon to view the data. What are the hypotheses for this test? O A. Ho: At least one of the means is different from the others. H₁ H₁ H₂ H3 OB. Ho: H₁ H₁: H1 H₂ =H3 H₂ H3 OC. Ho: H₁ H₂ H3 H₁: At least one of the means is different from the others. O D. Ho: H₁ H₂ H3 H₁: H₁ H₂ =H3 Data Table Type A 6.2 6.2 6.5 7.4 7.1 6.1 6.9 7.3 6.9 6.7 Print C Type B 7.7 7.5 8.7 8.1 8.6 8.8 8.4 8.5 Type C 8.5 9.3 9.6 9.1 9.1 9.1 9.8 9.5 9.9 Done O X
The data found below measure the amounts of greenhouse gas emissions from three types of vehicles. The measurements are in tons per year, expressed as CO2 equivalents. Use a 0.05 significance level to test the claim that the different types of vehicle have the same mean amount of greenhouse gas emissions. Based on the results, does the type of vehicle appear to affect the amount of greenhouse gas emissions? Click the icon to view the data. What are the hypotheses for this test? OA. Ho: H₁ H₂ H3 H₁: H₁ H₂ H3 OB. Ho: H₁ H₂ =H3 H₁: At least one of the means is different from the others. O C. Ho: At least one of the means is different from the others. H₁: H₁=H₂ =H3 OD. Ho: H₁ H₂ H3 H₁: H1₁ H₂ H3 Determine the test statistic. F = (Round to two decimal places as needed.) Identify the P-value. P-value= (Round to two decimal places as needed.) What is the conclusion of the test? the null hypothesis. Conclude that the type of vehicle Data Table C Type A 6.5 6.2 6.5 6.5 5.8 7.5 6.4 6.4 6.2 6.9…
Fertilizer: A new type of fertilizer is being tested on a plot of land in an orange grove, to see whether it increases the amount of fruit produced. The mean number of pounds of fruit on this plot of land with the old fertilizer was 381 pounds. Agriculture scientists believe that the new fertilizer may increase the yield. State the appropriate null and alternate hypotheses. Answer the following question.