An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass mA travels to the left with a speed of vA. Piece B with mass mBtravels to the right with speed vB. Show the velocity of piece B in terms of mA, mB and VA.Solution:Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so:pBf + pAf = 0Substituting the expression for momentum results tomBv_________ + _________mAv_________ = 0Deriving the expression for the velocity of piece B results tov_________=(mA/m_________)vA An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass ma travels to the left with a speed of vA. Piece B with mass mgtravels to the right with speed vB. Show the velocity of piece B in terms of mA, mB and VĄ.Solution:Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so:PBf + PAf = 0Substituting the expression for momentum results tomBV+mAV= 0Deriving the expression for the velocity of piece B results toV=(mA/mVA

The formula to calculate the initial momentum of the system is, pi=mu Here, pi is the initial…

An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass mA travels to the left with a speed of vA. Piece B with mass mBtravels to the right with speed vB. Show the velocity of piece B in terms of mA, mB and VA.

An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass mA travels to the left with a speed of vA. Piece B with mass mBtravels to the right with speed vB. Show the velocity of piece B in terms of mA, mB and VA.

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Question

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An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass m_A travels to the left with a speed of v_A. Piece B with mass m_Btravels to the right with speed v_B. Show the velocity of piece B in terms of m_A, m_B and V_A.

Solution:

Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so:

p_Bf+ p_Af= 0

Substituting the expression for momentum results to

m_Bv_________ + _________m_Av_{_________}= 0

Deriving the expression for the velocity of piece B results to

v_________=(mA/m_________)vA

An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass ma travels to the left with a speed of vA. Piece B with mass mg
travels to the right with speed vB. Show the velocity of piece B in terms of mA, mB and VĄ.
Solution:
Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so:
PBf + PAf = 0
Substituting the expression for momentum results to
mBV
+
mAV
= 0
Deriving the expression for the velocity of piece B results to
V
=(mA/m
VA

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