An article reports the following values for soil heat flux of eight plots covered with coal dust. 33.8 34.0 33.8 37.8 34.4 27.0 18.1 24.3 ЛUSE SALT The mean soil heat flux for plots covered only with grass is 29.0. Assuming that the heat-flux distribution is approximately normal, does the data suggest that the coal dust is effective in increasing the mean heat flux over that for grass? Test the appropriate hypotheses using α = 0.05. State the appropriate hypotheses. O Ho: μ = 29 Η μ < 29 H₂29 Ο Ηγ: μ = 29 Η μ = 29 O Ho: μ = 29 Ha: M = 29 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to three decimal places.) t = -.57 P-value .290 ×

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An article reports the following values for soil heat flux of eight plots covered with coal dust.
33.8
34.0 33.8 37.8 34.4 27.0 18.1 24.3
ЛUSE SALT
The mean soil heat flux for plots covered only with grass is 29.0. Assuming that the heat-flux distribution is approximately normal, does the data suggest that the coal dust is effective in increasing the mean heat
flux over that for grass? Test the appropriate hypotheses using α = 0.05.
State the appropriate hypotheses.
O Ho: μ = 29
Η μ < 29
H₂29
Ο Ηγ: μ = 29
Η μ = 29
O Ho: μ = 29
Ha: M = 29
Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to three decimal places.)
t = -.57
P-value .290
×
Transcribed Image Text:An article reports the following values for soil heat flux of eight plots covered with coal dust. 33.8 34.0 33.8 37.8 34.4 27.0 18.1 24.3 ЛUSE SALT The mean soil heat flux for plots covered only with grass is 29.0. Assuming that the heat-flux distribution is approximately normal, does the data suggest that the coal dust is effective in increasing the mean heat flux over that for grass? Test the appropriate hypotheses using α = 0.05. State the appropriate hypotheses. O Ho: μ = 29 Η μ < 29 H₂29 Ο Ηγ: μ = 29 Η μ = 29 O Ho: μ = 29 Ha: M = 29 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to three decimal places.) t = -.57 P-value .290 ×
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