An article reported the following data on oxidation-induction time (min) for various commercial oils: 86 101 130 160 180 195 134 145 215 105 145 151 153 139 87 99 95 119 129 A USE SALT Calculate the sample variance and standard deviation. (Round your answers to four decimal places.) 2= min2 %3D min If the observations were reexpressed hours, what would be the resulting values of the sample variance and sample standard deviation? Answer without actually performing the reexpression. (Round your answer to four decimal places.) hr2 hr

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An article reported the following data on oxidation-induction time (min) for various commercial oils:
86 101 130
160
180
195 134
145
215
105
145
151
153 139
87
99
95 119 129
A USE SALT
Calculate the sample variance and standard deviation. (Round your answers to four decimal places.)
52 =
min2
min
If the observations were reexpressed in hours, what would be the resulting values of the sample variance and sample standard deviation? Answer without actually performing the reexpression. (Round your answer to four
decimal places.)
52=
Ibr2
hr
Transcribed Image Text:An article reported the following data on oxidation-induction time (min) for various commercial oils: 86 101 130 160 180 195 134 145 215 105 145 151 153 139 87 99 95 119 129 A USE SALT Calculate the sample variance and standard deviation. (Round your answers to four decimal places.) 52 = min2 min If the observations were reexpressed in hours, what would be the resulting values of the sample variance and sample standard deviation? Answer without actually performing the reexpression. (Round your answer to four decimal places.) 52= Ibr2 hr
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